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4 years ago

Bonnie uses of

Mathematics

2 answers:

AfilCa [17]4 years ago

6 0

Bonnie will need 2025 g of sugar
1 Cup Sugar = 225 g
225 x 9 = 2025 g

jarptica [38.1K]4 years ago

3 0

Answer:

9 cups

Step-by-step explanation:

1 cup of sugar per each cupcake is 1 times N

N is how many cupcakes

N = 9

9 cups

honestly i dont think this is what u wanted

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4.6(x - 3) = -0.4x + 16.2

kolbaska11 [484]

Hey!

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Steps To Solve:

4.6(x - 3) = -0.4x + 16.2

~Distributive property

4.6x - 13.8 = -0.4x + 16.2

~Add 0.4 to both sides

4.6x - 13.8 + 0.4= -0.4x + 16.2 + 0.4

~Simplify

5x - 13.8 = 16.2

~Add 13.8 to both sides

5x - 13.8 + 13.8 = 16.2 + 13.8

~Simplify

5x = 30

Divide 5 to both sides

5x/5 = 30/5

~Simplify

x = 6

-----------------------------------------------

Answer:

$\large\boxed{x~=~6}$

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Hope This Helped! Good Luck!

8 0

3 years ago

Read 2 more answers

The product of two consecutive odd integers is 399. What equation would be used to solve

olga nikolaevna [1]

Step-by-step explanation:

the answer is in the image

6 0

3 years ago

2.5 X 10^5 divided by 1.0 X 10^10

bekas [8.4K]

Answer:

0.000025

Step-by-step explanation:

PEMDAS (Exponets first.)

10^5 = 100,000

10^10 = 10,000,000,000

rewrite

2.5 x 100,000 divided by 1.0 x 10,000,000,000

PEMDAS (multiplication next.)

2.5 x (10^5) = 250,000

1.0 x (10^10) = 10,000,000,000

rewrite.

250,000 divided by 10,000,000,000 = 0.000025

0.000025

6 0

3 years ago

PLEASE HELP!!

aliya0001 [1]

Ik this is late, but people who are looking for the answer can see this.

Answer:

an =1/3*6^n-1

Step-by-step explanation:

You should plug in 2 for n in each equation, which, the correct one should give you 2. Then, to make sure, you plug in 3 in the equations that gave you 2.

Example:

an = 1/3 * 6 ^n-1

Plug in 2.

an = 1/3 * 6 ^2-1

an = 1/3 * 6 ^1

1/3 * 6 = 2

Step 2.

an = 1/3 * 6 ^3-1

an = 1/3 * 6 ^2

1/3 * 36 = 12

Hope this helps.

4 0

3 years ago

How are percent transmittance and absorbance related algebraically?

statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:

A ∝ b · c

As Transmittance, $T =\dfrac{P}{P_0}$

% Transmittance, $\%T=100\times T$

Absorbance,

$A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T$

Hence, $A=\log_{10}\times \dfrac{1}{T}$ is the algebraic relation between absorbance and transmittance.

8 0

3 years ago