Answer:
Step-by-step explanation:
Numbers 1 and 4 are perimeter questions so all you do is add up all the sides and the label is cm. For #2, this is an area problem and the area for a rectangle is length times width, so multiply the 2 together and the label is inches squared. For #3, the volume formula for a cube is side*side*side and the label for this is feet cubed. For #5, the area for a triangle is .5 times the base times the height, and the label is mm-squared. That should help you get all the answers on your wn. Very, very simple.
Follow PEMDAS
multiplication is first (in this case) and then addition
2 x 8 = 16
16 + 2 = 18
18 is your answer
hope this helps
It would be the last option. I just worked the problem out and figured it out. I hope this helped! (:
A touchdown is scored 6 points for each touchdown and the points made after a touchdown is scored 2 points each. We are given the following variables:
t = number of touchdowns
p = number of points after a touchdown
Total score = 6t + 2p
Where 6 times t is the total score given by the number of touchdowns multiplied by 6 points, the same goes for the expression 2p.
Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
