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dem82 [27]
2 years ago
12

If f(1)=4 and f(n)= -2(n-1) -4 then find the value of f(5)

Mathematics
1 answer:
hoa [83]2 years ago
7 0

Answer: f(5) = 43

Step-by-step explanation:

You might be interested in
Pls help! Answer the question in the pic. I will mark brainliest and I will give 5 stars and a thanks.
LenKa [72]

Answer:

x = 10

Step-by-step explanation:

Use Pythagorean theorem to find the value of x

Focus only on one half of the triangle

if we slice the triangle in half, we get a right angle triangle

the base will now be 12/2 = 6

Pythagorean theorem says that a^2 + b^2 = c^2

plug 6 as a and 8 as b.

this should give you 100

now take the square root to find c (which equals x)

Ta-da!

5 0
2 years ago
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.895 g and a standard deviation
kvasek [131]

Answer:

3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 0.895, \sigma = 0.292, n = 37, s = \frac{0.292}{\sqrt{37}} = 0.048

Find the probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

This is the pvalue of Z when X = 0.809.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.809 - 0.895}{0.048}

Z = -1.79

Z = -1.79 has a pvalue of 0.0367

3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

5 0
2 years ago
Ms. Lynch has 21 coins in nickels and dimes.
bulgar [2K]

Answer:

Step-by-step explanation:So we know x + y = 21 and 5x +10y = 165 We line them up in columns    x +   y =   21  5x +10y = 165 To eliminate the x variable, I'll multiply every element in the 1st equation by -5. -5x + -5y = -105  5x + 10y =  165 Now we combine (add) the equations, which eliminates x altogether.  5y = 60   ...   y = 12 From there, x + 12 = 21  ...  x = 21-12  ...  x = 9 You should double check.  Do 9 nickles and 12 dimes equal $1.65? A very important thing to remember using this method is to do the same thing to each element in the equation that you change! I hope that helps.

4 0
2 years ago
The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours
ella [17]

Answer:

137

Step-by-step explanation:

Use the model A = Pe^(kt), where P is the initial number and k is the growth constant.  Then, in case 1,

300 = Pe^(k*3)

and in case 2,

4000 = Pe^(k*10).  We need to find P and e^k.

300 = Pe^(k*3) can be rewritten as (300/P) = [e^k]^3, which in turn may be solved for e^k:

∛(300/P) = e^k

Now we go back to 4000 = Pe^(k*10) and rewrite it as (4000/P) = [e^k]^10.  Substituting ∛(300/P) for e^k, we obtain:              

(4000/P) =  (300/P )^(10/3)

which must now be solved for P.  Raising both sides by the power of 3, we get:

(4000/P)^3 = (300/P)^10.  Therefore,

4000^3       300^10

------------- = -------------

   P^3             P^10

which reduces to:

4000^3       300^10

------------- = -------------

       1             P^7

or

        1         P^7

------------  =  -----------

4000^3       300^10

or:

           300^10

P^7 = ---------------- = 9.226*10^13  = 92.26*10^12

           4000^3

Taking the 7th root of both sides results in P = (92.26*10^12)^(1/7), or

                                                                        P = 137.26

The initial number of bacteria was 137.

7 0
3 years ago
PLSSSS HELPPPPPPPPPPPPPPP
g100num [7]

Answer:

i can hardly see that

Step-by-step explanation:

5 0
3 years ago
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