The answer will help you.
<span><span><span><span>13x</span>−<span>5x</span></span>+6</span>=<span>6+<span>8x
</span></span></span><span><span><span><span><span>13x</span>+</span>−<span>5x</span></span>+6</span>=<span>6+<span>8x
</span></span></span><span><span><span>(<span><span>13x</span>+<span>−<span>5x</span></span></span>)</span>+<span>(6)</span></span>=<span><span>8x</span>+<span>6
</span></span></span><span><span><span>8x</span>+6</span>=<span><span>8x</span>+6
</span></span><span><span><span>8x</span>+6</span>=<span><span>8x</span>+<span>6
</span></span></span><span><span><span><span>8x</span>+6</span>−<span>8x</span></span>=<span><span><span>8x</span>+6</span>−<span>8x
</span></span></span><span>6=6
</span><span><span>6−6</span>=<span>6−6
</span></span><span>0=<span>0
It has a real numbers are solutions.
And the answer is A.</span></span>
We can't see the whole question :/
2x2 + 8x - 12 = 0
4 + 8x - 12 = 0
8x = 12 - 4
8x = 8
x = 1
Answer:
In the last task, the result is 17+3x/6
Step-by-step explanation:
X+5/3 - 2x-7/6 + x/2
2(x+5)-(2x-7)+3x <em>/</em><em>6</em>
2x+10-2x+7+3x <em>/</em><em>6</em>
17+3x/6
I dunno this task above, I hope this one is correct :))
The power rule (or law of indices) related to root is given
![x^{ \frac{1}{2} }= \sqrt[2]{x}](https://tex.z-dn.net/?f=%20x%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%3D%20%20%5Csqrt%5B2%5D%7Bx%7D%20%20)
We have
Rewrite according to the rule we have
The exponent on y is '1'
