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natulia [17]
3 years ago
6

2x4-5x3-2x2+8x-1/2x-1

Mathematics
1 answer:
Zina [86]3 years ago
4 0

Answer: 2x^4-5x^3-2x^2+15x/2-1

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I need help like now !!
Kazeer [188]

Answer:

5

Step-by-step explanation:

6 0
3 years ago
Solve irrational equation pls
rusak2 [61]
\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)



\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\

4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\

There's one more condition I forgot about
-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\

Finally
x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}
3 0
2 years ago
Please help will give brainliest and 80 points
belka [17]

Answer:

Start

A2

B2

B1

C1

C2

D2

D3

D4

C4

END

Step-by-step explanation:

Start (A3)

x is equal to 141 because they are alternate interior angles.

A2. x is equal to 39 because they are corresponding angles.

B2. x would be supplementary to 41 because the angle that x supplements is corresponding to 41.

41 + x = 180 due to the linear pair postulate. Therefore, x = 139.

B1. x would be supplementary to 82 because they are consecutive exterior angles.

82 + x = 180 due to the linear pair postulate. Therefore, x = 98.

C1. x = 102 due to the vertical angles theorem.

C2. x would be supplementary to 130 because the angle that x supplements is equal to 130 (Alternate Exterior Angles).

130 + x = 180, x = 50.

D2. x = 74, corresponding angles.

D3. x = 83, corresponding angles.

D4. x = 95, corresponding

C4. x is supplementary to 18 because of the consecutive interior angles theorem.

x = 162

END

8 0
3 years ago
Read 2 more answers
Domain and range of Y=2x-1
LenaWriter [7]

Step-by-step explanation:

it would be 34y i got right answer

8 0
1 year ago
If you are going 43.5 miles per hour how many feet per second are you traveling?
Olenka [21]

Answer:

63.7999... (repeating) fps

Step-by-step explanation:

Feet per second (fps) per one (1) mph is 1.4666... repeating

so 43.5 * 1.46666... = 63.7999.. repeating

hope this helps:)

5 0
2 years ago
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