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Y_Kistochka [10]
3 years ago
5

How much would $150 invested at 8% interest compounded continuously be worth after 17 years

Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0

Answer:

Approximately $584.43

Step-by-step explanation:

Your formula is A=Pe^rt

A is what you're looking for, the amount

P is the principal aka what you put into the account: $150

e is the mathematical constant. You'd plug that into your calculator.

r is the rate, you'd put it into the equation as a decimal: 8%=.08

t is the time in years: 17

A=150e^.08x17 <em>you can plug this into your calculator</em>

A=$584.43

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erica [24]
If each square represents a square foot half of it would be .5 so then add all of them. The formula for Area is A=l•w and the Area formula for a triangle is A=hbb/2. Hope this helps :)
7 0
3 years ago
On the distant plant, Mathology, a sports area covers 7400 yodels2. How many square deckles would this be if 1 deckle = 75.9 yod
STatiana [176]

Answer:

It would be <u>97.50</u> square deckles.

Step-by-step explanation:

Given:

On the distant plant, Mathology, a sports area covers 7400 yodels².

1 deckle = 75.9 yodels.

Now, to get the square deckles.

As given, 1 deckle = 75.9 yodels.

So, to get the square deckles by using conversion factor:

<em>75.9 yodels = 1 deckle.</em>

7400 yodels² = 7400\div 75.9

                       = 97.50\ deckels ^2.

Therefore, it would be 97.50 square deckles.

8 0
3 years ago
i have been trying to solve this compound and double angle question please help me find the answer to these question guys​
natali 33 [55]

Answer:

These type of questions are super tricky b/c you have to remember all the different versions of the identities, and then they put the question in some odd form,  I feel like this should land math professors in jail , for dishonesty , b/c it's really a form of "how tricky can I make a question and still have a way to solve it"   anyway,

Step-by-step explanation:

a)

next the question asks   1-cos 2A   and this is total abuse of notation.   the way this should be written is   1- cos( 2A)  so we know that the A is part of the cosine functions input... btw.. in any computer program,  it would never ever let you get away with that top form of the expression.  :/   anyway... I keep ranting.. huh... sorry  :P

1-cos(2A) is an odd form of the identity  1/2(1-cos(2A) = sin^{2}(A)  the 1/2 is missing but we can add that pretty easy, we just have to remember to take it out too. I usually forget to do that. and my professor marks me off completely,  totally wrong, but I just miss one small thing  :/  anyway....

our 1-cos(2A) needs the 1/2 added to it.  or if we move that 1/2 to the other side it looks like  2*sin^{2}(A)  = 1-cos(2A)  and this is that "odd" from of the identity that I was talking about.  

next let's deal with sin(2A)  it has an identity of  2 sin(A)cos(A) which is really nice for us b/c it will cancel out the 2 in then numerator for us, nice !

now our fraction looks like  [2* sin^{2}(A)] / 2 sin(A)cos(A)

so cancel out one of the sines

2*sin(A) / 2 cos(A)

cancel the 2s

Sin(A) / Cos(A) = Tan(A)

nice  it worked out  :P

b)

by the above that we just worked out, then

Tan(15) = Sin(15) / Cos(15)

I had to look up what sin of 15 is b/c it's not one of those special angles but it does have an exact form of

Sin(15) = (√3 - 1) / 2√2

Cos(A) = (√3 + 1) / 2√2

you can use rule of Cos(A-B) = Cos(A)Cos(B)+Sin(A)Sin(B) to get the above and a similar rule for Sin(A-B)

back to our problem,  the 2√2 will cancel out

then we have

Tan(15) =  (√3 - 1) /(√3 + 1)

in the form that is above that's exact, the roots could be approximated but i'll just leave that in the form that is exact.  Most math professors like that form.  

 

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2 years ago
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Answer: -1/2

Step-by-step explanation:

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Run= 2

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3 years ago
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Alona [7]

Answer:

satisfy both equations

Step-by-step explanation:

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