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Aleks [24]
2 years ago
11

Prove that SinA×tanA/1-CosA=1+secA​

Mathematics
2 answers:
MariettaO [177]2 years ago
8 0

Answer:

Below.

Step-by-step explanation:

SinA×tanA/1-CosA

As tanA = sinA / cos A we have

sin^2A / cosA(1 - cosA)

= (1 - cos^2A) /  cosA(1 - cosA)

= (1 - cosA)(1 + cosA) / cosA(1 - cosA)

= (1 + cosA) /cos A

= 1 + 1/cosA

= 1 + secA.

=

Bad White [126]2 years ago
3 0

answer in the image....

hope it helps!!

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Answer:

(2,5)

Step-by-step explanation:

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3 years ago
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The area of a rectangle is 5/8 meter. The length of the garden is 1/5 meter. What is the width of the rectangle?
Afina-wow [57]

Width of rectangle is Width=\frac{25}{8} meters

Step-by-step explanation:

Area of rectangle = \frac{5}{8}

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Using the Formula:

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Putting values and finding width:

\frac{5}{8}=\frac{1}{5}*Width\\ Width=\frac{5}{8}\div\frac{1}{5}\\Width=\frac{5}{8}*\frac{5}{1}\\Width=\frac{25}{8} meters

So, width of rectangle is Width=\frac{25}{8} meters

Keywords: Area of rectangle

Learn more about Area of rectangle at:

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