Verify which of the following are identities.

How do I round 47,283 to the nearest 100,000

rosijanka [135]

The answer is zero.

Explanation:

The 4 is in the ten-thousands place.

Write the number 47,283 with an additional zero in the 100,000 place.

047,283

To round to the nearest 100,000, all digits to the right of the 100,000 place become zero. That means that the digits 47283 all become zero. Since 4 is less than 5, the digit to its left is not raised by 1, so the 100,000 place digit remains zero, and you end up with 000,000, which is simply 0.

Answer: 0

7 0

3 years ago

What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a

laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

$x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5$

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

$M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x$

So, the mean of 11 consecutive integers is the 6th integer.

4 0

4 years ago

I need to know the answer and how to solve this

AURORKA [14]

Answer:

135

Step-by-step explanation:

subtract 180 by 45 since a line is 180, that is what you get for the angle that is adjacent to angle 2, there is a rule if it is adjacent, they equal each other. thus, angle 2 is 135

5 0

3 years ago

(10

Anni [7]

Given:

The matrix multiplication

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

To find:

The order of resulting matrix.

Solution:

We know that, if order of first matrix is $m_1\times n_1$ and the order of second matrix is $m_2\times n_2$ , then the order of these two matrices is $m_1\times n_2$ .

We have,

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

Here, the order of first matrix is $2\times 3$ and the order of the second matrix is $3\times 1$ . So, the order of the second matrix is $2\times 1$ . It is also written are 2 by 1.

Therefore, the correct option is A.

6 0

3 years ago

Read 2 more answers

Which expressions are equivalent to 6 (–x) 2x (–7) 2x? Check all that apply. X x 6 – 7 x 2x 2 x 3 – x 2x – 4 2x x – 1 x 1.

qaws [65]

Equivalent expression is the expression which is equal to the original equation but the way of representation is different. The equivalent expression of the given expression are,

$x+x+6-7+x$

$3-x+2x-4+2x=3x-1$

Given information

The given expression in the problem is,

$6+(-x)+2x+(-7)+2x$

<h3>Equivalent expression</h3>

Equivalent expression is the expression which is equal to the original equation but the way of representation is different.

The given equation is,

$6+(-x)+2x+(-7)+2x$

As the product of the negative and positive is negative. Thus solve the equation by opening the bracket.

$6+(-x)+2x+(-7)+2x=6-x+2x-7+2x\\
6+(-x)+2x+(-7)+2x=-x+2x+2x+6-7\\
6+(-x)+2x+(-7)+2x=3x-1$

Check all the option,

1) The expression given in the option 1 is,

$x+x+6-7+x$

Solve it further,

$x+x+6-7+x=x+x+x+6-7\\
x+x+6-7+x=3x-1\\$

The result is equal to the result of the given expression. Thus the expression of the option 1 is equivalent to the expression given in the problem.

2) The expression given in the option 2 is,

$2x+2+x$

Solve it further,

$2x+2+x=2x+x+2\\2x+2+x=3x+2$

The result is not equal to the result of the given expression. Thus the expression of the option 2 is not equivalent to the expression given in the problem.

3) The expression given in the option 3 is,

$3-x+2x-4+2x$

Solve it further,

$3-x+2x-4+2x=3x-1$

The result is equal to the result of the given expression. Thus the expression of the option 3 is equivalent to the expression given in the problem.