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d1i1m1o1n [39]
3 years ago
15

Please help ASAP!

Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

I think

Step-by-step explanation:

If you chose Isosceles Right Triangle Reflection to prove ASA Congruence,. You can use the distance formula to show congruency for the sides. To show an angle is congruent to a corresponding angle, use your compass and straightedge.

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Time = -b/2a = 3. f(3) = 24.

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3 years ago
Mai made $112 for 8 hours of work.
vodomira [7]

Answer:

18 hours

Step-by-step explanation:

3 0
3 years ago
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What is the discrimination of the quadratic equation 6x^2-9x-8=0
aleksklad [387]

Answer:

first setup your problem. it should look like this :

6 0
3 years ago
A chemical factory has 2 cylindrical chemical tanks, one containing Chemical X and the other containing Chemical Y. The tank con
Mashutka [201]
The tank with Chemical X "takes up" a space of 25ft³.  Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume.  The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:
\frac{25}{1.5}=\frac{1.5V}{1.5} \\16 \frac{2}{3}=V
To find the volume of a cylinder, we find the base area and multiply by the height.  We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:
16 \frac{2}{3}=3.2h \\ 16 \frac{2}{3}=3 \frac {2}{10}h
We would now divide both sides by 3 2/10:
\frac{16 \frac{2}{3}}{3 \frac{2}{10}}= \frac{3 \frac{2}{10}h}{3 \frac{2}{10}}
This is the same as:
\frac{\frac{50}{3}}{\frac{32}{10}}=h \\ \\ \frac{50}{3}* \frac{10}{32}=h \\ \\ \frac{500}{96}
So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.
8 0
3 years ago
A plane at an altitude of 7000 feet is flying in the direction of an island. If the angle of elevation is 21 degrees from the pl
sleet_krkn [62]

Answer:

6,535.06 feet

Step-by-step explanation:

The set up is right angles

hypotenuse = 7000feet

angle of elevation = 21 degrees

Required

horizontal distance (adjacent)

Using SOH, CAH TOA trig identity

cos theta = adj/hyp

cos 21 =  adj/7000

adj = 7000 cos 21

adj = 7000(0.9336)

adj =  6,535.06

Hence the HORIZONTAL distance until the plane flies over the island is 6,535.06 feet

5 0
3 years ago
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