Answer:
18 hours
Step-by-step explanation:
Answer:
first setup your problem. it should look like this :
The tank with Chemical X "takes up" a space of 25ft³. Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume. The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:

To find the volume of a cylinder, we find the base area and multiply by the height. We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:

We would now divide both sides by 3 2/10:

This is the same as:

So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.
Answer:
6,535.06 feet
Step-by-step explanation:
The set up is right angles
hypotenuse = 7000feet
angle of elevation = 21 degrees
Required
horizontal distance (adjacent)
Using SOH, CAH TOA trig identity
cos theta = adj/hyp
cos 21 = adj/7000
adj = 7000 cos 21
adj = 7000(0.9336)
adj = 6,535.06
Hence the HORIZONTAL distance until the plane flies over the island is 6,535.06 feet