That is a difference of two square numbers, we can factorize them easily:
<span>0 =-b^2 + 25
b^2 - 25 = 0
(b + 5)(b - 5) = 0</span>
So the class must have at least 5 more students.
Answer:
![27^{\frac{1}{5} }=\sqrt[5]{3^3}](https://tex.z-dn.net/?f=27%5E%7B%5Cfrac%7B1%7D%7B5%7D%20%7D%3D%5Csqrt%5B5%5D%7B3%5E3%7D)
Step-by-step explanation:
we are given
we can use rule to change exponent into radical
![\sqrt[n]{a} =a^{\frac{1}{n} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D)
so, we can write as
now, we can use rule
and we can write our term as
Answer:
(-12, -20).
Step-by-step explanation:
A dilation of factor 4 moves (-3, 5) to (-3*4, 5*4) = the point (-12, 20).
A reflection over the x-axis is (x, y) ------> ( x, -y).
So ( -12, 20) goes to (-12, -20).
Please view my other solution I gave you.
:)
But I will still answer this if you see it.
Because 0.8^x is never 0, then the asymptote is 0-10 or -10.
