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3 years ago

Plz help me! Thanks!

Mathematics

1 answer:

beks73 [17]3 years ago

7 0

Answer:

1 i think

Step-by-step explanation:

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What the perimeter of this

olga2289 [7]

D) 142 (i can't make the square root symbol)

/18 = 3/2
(3/2 + 4/2) x 2 = 14/2

6 0

3 years ago

Please help me im stuckkm

Marrrta [24]

Answer:

Below in bold.

Step-by-step explanation:

(a) Using the Pythagoras theorem:

30^2 = 21^2 + p^2

p^2 = 30^2 - 21^2 = 459

p = √459

= 21.4 cm to nearest tenth.

(b) cos P = 21/30 = 0.70

m < P = 45.57 degrees to nearest hundredth.

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2 years ago

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Regina has wet weather on about 3/10 of the days in a year. It has wet weather on about four times as many days as it has fog. O

salantis [7]

I would have to say 4/10. hope this helps

5 0

3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

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3 0

1 year ago

Lines m and n are parallel. Which angle has a measure of 110°?

grigory [225]

This might help you..need more information

6 0

3 years ago