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2 years ago

Plz help me! Thanks!

Mathematics

1 answer:

beks73 [17]2 years ago

7 0

Answer:

1 i think

Step-by-step explanation:

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Solve for x in the picture please

Nutka1998 [239]

Answer: $x=1$

Step-by-step explanation:

In order to find the value of "x", it is important to remember that:

$Tangent\ chord\ angle=\frac{1}{2}(Intercepted\ arc)$

We can identify in the figure that:

$Tangent\ chord\ angle=(43x)\°\\\\Intercepted\ arc=AB$

Then:

$43x=\frac{1}{2}AB$

Solving for AB:

$2(43x)=AB\\\\AB=86x$

Now, since there are 360° in a circle, we know that:

$AB+(272x+2)=360$

Then we can substitute $AB=86x$ into $AB+(272x+2)=360\°$ and solve for "x". This is:

$(86x)+(272x+2)=360\\\\358x=360-2\\\\x=\frac{358}{358}\\\\x=1$

8 0

3 years ago

0.66666667 as a fraction

Ierofanga [76]

Answer:

__________________________________________

The correct answer is: " $\frac{2}{3}$ " .

__________________________________________

Note: Let's assume that this given decimal value is really:

"0.66666666666666666....." ;

(non-terminating; but repeating the singing digit, "7" ; yet rounded to:

" 0.66666667 " ;

then: " 0.666... " = $\frac{666}{999}$ ;

= (666 ÷ 111) / (999 ÷ 111) ;

= 6/9 ;

= (6÷3)/(9÷3) ;

= 2/3 ;

= " $\frac{2}{3}$ "

→ which is our answer.

____________________________________________

Or: " 0.6666... " = 666 ÷ 999 = ? ;

using calculator :

= 0.66666667 ;

→ which is the "rounded off" number of "0.6666..." ;

— (infinitely repeating) ;

→ So 666 ÷ 999 =

→ " $\frac{666}{999}$ " ;

= " $\frac{2}{3}$ " ;

→ Either use a "fraction calculator" ;

or simplify as aforementioned.

____________________________________________

Hope this answer is helpful to you!

Best wishes to you in your academic pursuits

— and within the "Brainly" community!

____________________________________________

7 0

2 years ago

Read 2 more answers

X/6=x/7-5 Please show work thank you so much!!

stiv31 [10]

Step-by-step explanation:

hope u like it plz follow and give thanks

5 0

2 years ago

How do I do this? (3x^2+8)-(2x^2+1) So first I add like terms? 5x^2 + 8 + 1

Gemiola [76]

(3x² + 8) - (2x² + 1)
= 3x² + 8 - 2x² - 1
= 3x² - 2x² + 8 - 1
= x² + 7

3 0

2 years ago

Calculus question?

Ann [662]

Remark
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)

Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.

Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.

I suppose this is possible.
y' = 3/x^(1/2) + 6x

y' = $\frac{3 + 6x^{3/2}}{x^{1/2}}$

Frankly I like the first answer better, but you have a choice of both.

5 0

2 years ago