Wasssaa,
Steps:
To find the area of a triangle you multiply the base times the height, in this case the is (19m)
and the height is (11m), after you multipy those numbers you divide by (2)
![(19m \times 11m) \div 2](https://tex.z-dn.net/?f=%2819m%20%5Ctimes%2011m%29%20%5Cdiv%202)
![\frac{209 }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B209%20%20%7D%7B2%7D%20)
Answer:
![104.5sq \: m](https://tex.z-dn.net/?f=104.5sq%20%5C%3A%20m)
Hope this helped you
:D
There are
ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are
ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's
way of doing that.
So we have
![\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520](https://tex.z-dn.net/?f=%5Cdbinom%7B10%7D2%5Cdbinom83%5Cdbinom55%3D%5Cdfrac%7B10%21%7D%7B2%21%2810-2%29%21%7D%5Cdfrac%7B8%21%7D%7B3%21%288-3%29%21%7D%5Cdfrac%7B5%21%7D%7B5%21%285-5%29%21%7D%3D2520)
The last expression has a more compact form in terms of the so-called multinomial coefficient,
![\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520](https://tex.z-dn.net/?f=%5Cdbinom%7B10%7D%7B2%2C3%2C5%7D%3D%5Cdfrac%7B10%21%7D%7B2%213%215%21%7D%3D2520)
498 is approximately 500
12 is approximately 10
500/10 = 50
So, 498/12 is approximately 50.
Answer:
c and d
Step-by-step explanation:
Your answer would be <u>Ninety seven and sixty ninths.</u> Hope this helps!