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amid [387]
2 years ago
6

Write the equation of a rational function f(x) = p(×)/q(x) having the indicated properties, in which the degrees of p and q are

as small as possible. More than one correct function may be possible. Graph your function using a graphing utility to verify that it has the required properties.
134.) f has a vertical asymptote given by x=3, a horizontal asymptote y=0, y-intercept at -1, and no x-intercept

135.) f has vertical asymptotes given by x=-2 and x=2, a horizontal asymptote y=2, intercept at 9/2, x-intercepts at -3 and 3, and y-axis symmetry

Please helppp, thank youu​

Mathematics
1 answer:
stellarik [79]2 years ago
6 0

Answer:

134. y = 3 / (x-3)    attachment picture 1

135. y = (2*(x+3)(x-3)) / (x+2)(x-2)    attachment picture 2

Step-by-step explanation:

134. y = 3¹ / (x¹-3)

135. y = (2*(x+3)(x-3)) / (x+2)(x-2)

Apply the asymptote properties to verify, such as compare the degree of numerator and denominator... denominator approach 0  etc.

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If there are 80 pages in this weeks edition, how many pages can she predict will have advertisements
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There are two different loci that cause white coat color in horses. One locus is the albino locus found in all mammals. Albinism
julsineya [31]

Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.

Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w.  Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:

1/16 CCWW (lethal)

2/16 CCWw (white)

2/16 CcWW (lethal)

4/16 CcWw (white)

1/16 CCww (normal)

2/16 Ccww (normal)

2/16 ccWw (albino)

1/16 ccWW (lethal)

1/16 ccww (albino)

Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.

8 0
3 years ago
ANSWER ASAP!! Find the area of a triangle with legs that are: 12 m, 15 m, and 9 m.
Setler79 [48]

Answer:

<h2>54m²</h2>

Step-by-step explanation:

<h3>METHOD 1:</h3>

You can use the Heron's formula:

A=\sqrt{p(p-a)(p-b)(p-c)}

where

<em>p</em><em> - half of perimeter</em>

<em>a, b, c</em><em> - lengths of sides</em>

We have

a=12m;\ b=15m;\ c=9m

Calculate:

p=\dfrac{12+15+9}{2}=\dfrac{36}{2}=18\ (m)\\\\A=\sqrt{18(18-12)+(18-15)(18-9)}\\\\A=\sqrt{(18)(6)(3)(9)}\\\\A=\sqrt{2916}\\\\A=54\ (m^2)

<h3>METHOD 2:</h3>

Let's check that it is not a right triangle.

If the sum of the squares of the two shorter sides is equal to the square of the longest side, then this triangle is rectangular.

We have

9m < 12m

Check:

9^2+12^2=81+144=225\\15^2=225

This is a right trianglr wherew 9m and 12m are legs and 15m is a hypotenuse.

The formula of an area of a right triangle is:

A=\dfrac{ab}{2}

<em>a, b</em><em> - legs</em>

Substitute:

A=\dfrac{(9)(12)}{2}=\dfrac{108}{2}=54\ (m^2)

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