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amid [387]
3 years ago
6

Write the equation of a rational function f(x) = p(×)/q(x) having the indicated properties, in which the degrees of p and q are

as small as possible. More than one correct function may be possible. Graph your function using a graphing utility to verify that it has the required properties.
134.) f has a vertical asymptote given by x=3, a horizontal asymptote y=0, y-intercept at -1, and no x-intercept

135.) f has vertical asymptotes given by x=-2 and x=2, a horizontal asymptote y=2, intercept at 9/2, x-intercepts at -3 and 3, and y-axis symmetry

Please helppp, thank youu​

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

134. y = 3 / (x-3)    attachment picture 1

135. y = (2*(x+3)(x-3)) / (x+2)(x-2)    attachment picture 2

Step-by-step explanation:

134. y = 3¹ / (x¹-3)

135. y = (2*(x+3)(x-3)) / (x+2)(x-2)

Apply the asymptote properties to verify, such as compare the degree of numerator and denominator... denominator approach 0  etc.

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"5 to the second power", what does the exponent 2 tell us to do with the<br> base 5?
masha68 [24]

Answer:

The exponent 2 tells us that we must multiply 2 five's together.

So we have: 5^2 = 5 x 5

Let me know if this helps!

7 0
3 years ago
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Alan is building a garden shaped like a rectangle with a semicircle attached to one short side. If he has 70 feet of fencing to
viktelen [127]

The dimension that would give the maximum area is 20.8569

<h3>How to solve for the maximum area</h3>

Let the shorter side be = x

Perimeter of the semi-circle is πx

Twice the Length of the longer side

[70-(\pi )x -x]

Length = [70-(1+\pi )x]/2

Total area =

area of rectangle + area of the semi-circle.

Total area =

x[[70-(1+\pi )x]/2] + [(\pi )(x/2)^2]/2

When we square it we would have

70x +[(\pi /4)-(1+\pi)]x^2

This gives

70x - [3.3562]x^2

From here we divide by 2

35x - 1.6781x^2

The maximum side would be at

x = 35/2*1.6781

This gives us 20.8569

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7 0
2 years ago
Question 3
solmaris [256]
Easy, 15 feet. If he dived 12 the first time and three more than his first the second time you just have to add 3 + 12
3 0
4 years ago
A 40% antifreeze solution is to be mixed with a 70% antifreeze
Alenkasestr [34]

Answer: 160 liters of the

40% solution and 80 liters of the 70% solution will be used.

Step-by-step explanation:

Let x represent the number of liters of 40% antifreeze solution that should be used.

Let y represent the number of liters of 70% antifreeze solution that should be used.

The volume of the mixture to be mixed is 240 liters. It means that

x + y = 240

The 40% antifreeze solution is to be mixed with a 70% antifreeze

solution to get 240 liters of a 50% solution. This means that

0.4x + 0.7y = 0.5(240)

0.4x + 0.7y = 120 - - - - - - - - - - - -1

Substituting x = 240 - y into equation 1, it becomes

0.4(240 - y) + 0.7y = 120

96 - 0.4y + 0.7y = 120

- 0.4y + 0.7y = 120 - 96

0.3y = 24

y = 24/0.3

y = 80

x = 240 - y = 240 - 80

x = 160

7 0
3 years ago
A snack-size bag of M&amp;Ms candies contains 14 red candies, 10 blue, 5 green, 11 brown, 3 orange, and 12 yellow. If a candy is
Nitella [24]

Answer:

The odds of getting a green M&M  is \frac{1}{10} and  the probability of getting a green M&M  is \frac{1}{11}

Step-by-step explanation:

Red candies = 14

Blue candies = 10

Green candies =  5

Brown candies = 11

Orange candies = 3

Yellow candies = 12

Total No. of candies = 14+10+5+11+3+12 = 55

(a) the odds of getting a green M&M

Green candies = 5

Total number of candies excluding green or unfavorable = 50

Odds of getting a green M&M  = \frac{\text{favorable outcome}}{\text{Unfavorable outcomes}}

                                                   = \frac{5}{50}

                                                   = \frac{1}{10}

(b) the probability of getting a green M&M

Green candies = 5

Total No. of candies = 55

So,  the probability of getting a green M&M =\frac{5}{55}

                                                                        =\frac{1}{11}

Hence the odds of getting a green M&M  is \frac{1}{10} and  the probability of getting a green M&M  is \frac{1}{11}

4 0
3 years ago
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