128 adult tickets were sold
- y=x+2.....(1)
- y+1= – 4x......(2)
Put value of y in Equation 1 in Equation 2.
![\looparrowright \sf y + 1 = - 4x](https://tex.z-dn.net/?f=%20%5Clooparrowright%20%5Csf%20y%20%2B%201%20%3D%20%20-%204x)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf (x + 2) + 1 = - 4x](https://tex.z-dn.net/?f=%20%5Clooparrowright%20%5Csf%20%28x%20%2B%202%29%20%2B%201%20%3D%20%20-%204x)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf x + 2 + 1 = - 4x](https://tex.z-dn.net/?f=%20%5Clooparrowright%20%5Csf%20x%20%2B%202%20%2B%201%20%3D%20%20-%204x)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf x +3= - 4x](https://tex.z-dn.net/?f=%20%5Clooparrowright%20%5Csf%20x%20%2B3%3D%20%20-%204x)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf x + 4x= - 3](https://tex.z-dn.net/?f=%20%5Clooparrowright%20%5Csf%20x%20%20%2B%204x%3D%20%20-%203)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf 5x= - 3](https://tex.z-dn.net/?f=%5Clooparrowright%20%5Csf%205x%3D%20%20-%203)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf x= \dfrac{ - 3}{5}](https://tex.z-dn.net/?f=%5Clooparrowright%20%5Csf%20x%3D%20%20%20%5Cdfrac%7B%20-%203%7D%7B5%7D%20)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
Let's find value of y :
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf y=x+2](https://tex.z-dn.net/?f=%5Clooparrowright%20%5Csf%20y%3Dx%2B2)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf y= \dfrac{ - 3}{5} +2](https://tex.z-dn.net/?f=%5Clooparrowright%20%5Csf%20y%3D%20%5Cdfrac%7B%20-%203%7D%7B5%7D%20%2B2)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf y= \dfrac{ - 3 + 10}{5}](https://tex.z-dn.net/?f=%5Clooparrowright%20%5Csf%20y%3D%20%5Cdfrac%7B%20-%203%20%2B%2010%7D%7B5%7D%20)
![\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20)
![\looparrowright \sf y= \dfrac{7}{5}](https://tex.z-dn.net/?f=%5Clooparrowright%20%5Csf%20y%3D%20%5Cdfrac%7B7%7D%7B5%7D%20)
Solution:
![\looparrowright \sf \bigg( \dfrac{ - 3}{5} , \dfrac{7}{5} \bigg)](https://tex.z-dn.net/?f=%5Clooparrowright%20%5Csf%20%20%5Cbigg%28%20%20%5Cdfrac%7B%20-%203%7D%7B5%7D%20%2C%20%5Cdfrac%7B7%7D%7B5%7D%20%20%5Cbigg%29)
Step-by-step explanation:
so we can't do anything with this, what is the task
Answer:
0.13
Step-by-step explanation:
First let's find the probability of finding the first species or the second species:
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 0.61 + 0.08 - 0.28
P(A or B) = 0.41
Then, to find the probability of finding one or another but not both, we just need the symmetric difference of the events, that is: P(A or B) - P(A and B):
P(A or B) - P(A and B) = 0.41 - 0.28 = 0.13
You can factor out a six since both 6 and 48 can be divided by 6. Take out the six from the expression, basically dividing both six and 48 by 6, and keep the rest of the expression in parentheses:
6(y^2+8)