Answer:
100
Step-by-step explanation:
Given : 
To Find : the value of expression 5a.
Solution :
We are given the value of 'a' i.e. a=20
Now to find the value of given expression 5a
⇒
put a = 20 in the equation
⇒
⇒
⇒
Thus , The value of expression 5a when a = 20 is 100
Answer:
Domain - (0,1,2,3,4) Range - (32,27,22,17,12)
Domain - (0,1,2,3,4) Range - (36,32,28,24,20)
Step-by-step explanation:
The # of knots is actually the X values which is also the definition of the word, "Domain" whilst the Length of the ropes is the y values, aka the range.
Siras ! Don't try to picture this all in your head !
You'll wear out your brain.
You MUST sketch it on a piece of paper.
Draw an x-axis and a y-axis, then draw the two circles.
I'm drawing myself a picture right now, and I'm
supposed to be some kind of a genius.
a). In order to move Circle-Q so that both centers are
at the same point, you need to move the center of Q
4 units down and 2 units to the right.
When you do that, you'll have the little circle inside the
big circle, with their centers both at the same place.
b). The radius of Q is 2.
The radius of P is 20.
What do you have to multiply 2 by, in order to get 20 ?
THAT's the scale factor to dilate Q so that it has the same
radius as P.
When you do that, suddenly it'll look like you only have one circle
on the paper ... they'll both have the same radius and their centers are
at the same place, so you can't tell them apart.
c). All circles are similar !
I went online (you could easily go there too). I searched the question
"Are circles similar ?" and a lot of interesting stuff came up. (you could
do that too). I saw a lot of ways to prove that all circles are similar.
The best one says:
Two figures are "similar" if you can make one of them
exactly fit on top of the other one (make them congruent)
with translations and dilations.
You just did that with P and Q !
-- Translation is moving them around.
You moved Q and put the centers of both circles at the same place.
-- Dilation is blowing it up or blowing it down, so its size changes
but its shape doesn't change.
You blew Q up so that it had the same radius as P.
Then the two circles exactly fit over/under each other.
So the two circles are similar.
The domain is the set of all possible x-values which will make the function "work", and will output real y-values
there is not a value for x, that makes the function does not "work", so x can take any value, in other words all real numbers
so, the answer is all real numbers
