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balu736 [363]
3 years ago
9

I need help trying to figure how to solve this equation it's 26-2x÷4+6 <1

Mathematics
1 answer:
larisa [96]3 years ago
6 0
Hello there.

<span>I need help trying to figure how to solve this equation it's 26-2x÷4+6 <1

First, </span><span> Simplify both sides

Next, </span><span>Subtract 32 from both sides

Then, </span><span>Multiply both sides by 2 over -1

Final Answer: </span>x > <span>62</span>
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miskamm [114]

Answer:

\frac{3^{12}}{3^{10}}

Step-by-step explanation:

+ or x you plus the indices

- or divide you minus the indices

so 3^8 x 3^4 would be 3^12

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11

Step-by-step explanation:

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If (x + 8) is a factor of f(x), which of the following must be true?
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Answer:

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Step-by-step explanation:

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mars1129 [50]

Answer:

\frac{-3x^2-7x-4}{x^3-2x^2-9x+18}

Step-by-step explanation:

\frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}

Factor x²-9 and x²-5x+6.

\frac{2}{\left(x+3\right)\left(x-3\right)}-\frac{3x}{\left(x-2\right)\left(x-3\right)}

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Adjust the fractions based on LCM.

\frac{2\left(x-2\right)}{\left(x+3\right)\left(x-3\right)\left(x-2\right)}-\frac{3x\left(x+3\right)}{\left(x-2\right)\left(x-3\right)\left(x+3\right)}

Subtract the fractions since denominators are equal.

\frac{2\left(x-2\right)-3x\left(x+3\right)}{\left(x+3\right)\left(x-3\right)\left(x-2\right)}

Expand.

\frac{-3x^2-7x-4}{x^3-2x^2-9x+18}

The fraction can be in factored form.

\frac{-\left(x+1\right)\left(3x+4\right)}{\left(x-2\right)\left(x+3\right)\left(x-3\right)}

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