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Elena-2011 [213]
3 years ago
5

PLZ HURRY 30 POINTS!!!!!!

Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0

Answer:

has a slope of 1/3 and passes through the point (-3, 1)

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Adam bought three kinds of
DENIUS [597]

9514 1404 393

Answer:

  35

Step-by-step explanation:

The 16 onion bagels are twice as many as plain bagels, so there were 8 plain bagels.

There were 4 more sesame bagels than plain bagels, so there were 12 sesame bagels.

Adam has 8 plain, 12 sesame, and 15 onion bagels left, for a total of 35 bagels left.

8 0
3 years ago
Brooke has to set up 70 chairs in equal rows for the classtalent show. There is not enough room for more than 20 rows. What are
Leya [2.2K]
you can have 14 rows with 5 chairs in each row. 14x5=70. hope i helped
4 0
4 years ago
Read 2 more answers
P² 13p=-30 menentukan nilai p
garri49 [273]
I hope this helps you

4 0
4 years ago
Only answer if you are sure!!
bezimeni [28]
Answer

standard deviation

Explanation

Standard deviation is the measure of spread of data around the mean.

Mode is the most common value - which would be the mean in a normal-like distribution.

Median is the middle value when the data is ranked in ascending order (or descending even)

Skewness, is when the mode of the data falls behind the mean by a large margin.

An example is GDP, a few billionaires increase the number number and distort it, even though most people are of low or middle based income.
8 0
3 years ago
A study reveals that 65% of homeowners in Omaha own a lawn mower. To test this claim, you form a sample of 500 homeowners in Oma
kotegsom [21]

Answer:

There is no enough evidence to reject the claim using a level of significance of 5%

Step-by-step explanation:

Let p be the true proportion of homeowners in Omaha who own a lawnmower. We want to test  

H_{0}: p = p_{0} = 0.65 vs H_{1}: p\neq 0.65 (two-tailed alternative).

We have a large sample of size n = 500 and a point estimate for p is \hat{p}=0.68. The test statistic is given by

Z=\frac{\hat{p}-p_{0}}{\sqrt{p_{0}(1-p_{0})/n}}=\frac{0.68-0.65}{\sqrt{0.65(1-0.65)/500}} where \sqrt{0.65(1-0.65)/500} is the standard error of \hat{p} when H_{0} is true. The observed value is z_{0} = 1.4064 which comes from a standard normal distribution. Because we want to use a level of significance of 5%, our rejection region is RR={z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles respectively. Because 1.4064 does not belong to RR, we fail to reject the null hypothesis.

6 0
3 years ago
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