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3 years ago

How do you solve this problem.

Mathematics

2 answers:

Nat2105 [25]3 years ago

8 0

Answer:

8 were yoused because 8 times 3 =24 so if you subtract you get 8

Step-by-step explanation:

Nitella [24]3 years ago

7 0

Answer:

144

Step-by-step explanation:

3/4 of the dinner tables are full (each table is 3/4 full)

3/4 of 8 =6

6*24 =144

3/4 of the dinner tables are full (3/4 of all tables)

3/4 of 24 =18

18*8=144

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For the expression, use a property to write an equivalent expression, tell which property you used. Please help, and thank you :

raketka [301]

What about if you use the distributive property? You could do 1(x+13) because the 1 would distribute to the x and the 13 making it x+13. Hope that is helpful.

4 0

3 years ago

A partnership owned equally by 16 partners is worth $1.6 million. The partnership loses a lawsuit worth $6 million. What is the

Marizza181 [45]

Answer:

6250

Step-by-step explanation:

if each partner has a even number of money from 1.6 million, that each person had $100,000, and to pay the lawsuit evenly than each person will have to pay $6250.

1.6 mill divided by 16= 100,000

6 mill divided by 16= 6250.

4 0

3 years ago

In parallelogram LMNP if PQ=21 find QM.

Simora [160]

Answer:

QM = 21

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, then

QM = PQ = 21

8 0

3 years ago

the scale on a map is 1:240000. What is the actual distance represented by 1 centimetre. Give your answer in kilometres

allsm [11]

Answer:

0.24 kilometres

Step-by-step explanation:

1cm represents 240000cm on actual map

therefore to get the actual representation

1km=1000000cm

? =240000cm

Do cross multiplication;

(240000cm x 1km)/1000000cm

=0.24km

5 0

2 years ago

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

3 years ago