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Stolb23 [73]
3 years ago
13

Solve this please! Will give correct answer brainiest!

Mathematics
2 answers:
k0ka [10]3 years ago
3 0

Answer:

it is $5 per hour

PSYCHO15rus [73]3 years ago
3 0

Answer:

It is c.

Step-by-step explanation:

Divide the amount earned by hours. For example 10/2=5, 20/4=5, 30/6=5 and so on

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Covert 3.92 into a mixed number in simplest from
Kobotan [32]
First, take three off it, because that will form the whole-number part:
3.92 = 3 + 0.92

Next, read off the place value of the last digit. The 2 is in the 'hundredths' column, which means that 0.92 = 92/100:
3.92 = 3 + 92/100

Finally, simplify 92/100 by dividing top and bottom by 4 to get 23/25. Then, shove it all together:
3.92 = 3 23/25
8 0
3 years ago
Read 2 more answers
Rationalize the denominator of sqrt -9 / (4-7i) - (6-6i) ...?
Colt1911 [192]
√(- 9 ) / (( 4 - 7 i ) - ( 6 - 6 i )) = 3 i / ( 4 - 7 i - 6 + 6 i ) =
= 3 i / ( - 2 - i ) = - 3 i / ( 2 + i ) =
= \frac{-3i}{2 + i}* \frac{2 - i}{2 - i}= \\ =   \frac{-6i+3i ^{2} }{2- i^{2} }= \\ = \frac{-3-6i}{2+1}= \frac{-3-6i}{3}=
= - 1 - 2 i

5 0
3 years ago
I need help understanding how to do this problem (image attached).
ikadub [295]
Well to find the value of the interior angle of a hexagon it would be out of a total of 720 degrees therefore just subtract the values of the known interior angle values and you should be able to get the value of the interior angle of X
4 0
3 years ago
What are the x intercepts of the following function:
Anon25 [30]

Answer:

2 and -1 so it would be the first choice

A)

Step-by-step explanation:

3 0
2 years ago
Find the average value of f over region
yan [13]
The area of D is given by:

\int\limits \int\limits {1} \, dA = \int\limits_0^7 \int\limits_0^{x^2} {1} \, dydx  \\  \\ = \int\limits^7_0 {x^2} \, dx =\left. \frac{x^3}{3} \right|_0^7= \frac{343}{3}

The average value of f over D is given by:

\frac{1}{ \frac{343}{3} }  \int\limits^7_0  \int\limits^{x^2}_0 {4x\sin(y)} \, dydx  = -\frac{3}{343}  \int\limits^7_0 {4x\cos(x^2)} \, dx  \\  \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49
3 0
3 years ago
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