Write the equation of the line containing the points (3, 6) and (7, - 2) in standard form.

Mathematics

2 answers:

Rama09 [41]2 years ago

7 0

Answer:

$y = mx + c \\ 6 = 3m + c...(1) \\ - 2 = 7m + c...(2) \\ subtract \: (2) - (1) \\ 4m = - 8 \\ \therefore \: m = - 2 \: sub \: in \: (1) \\ 6 = 3( - 2) + c \\ \therefore \: c = 12 \\ \boxed{y = - 2x + 12}$

kondaur [170]2 years ago

4 0

Answer:

y=-2x+12

Step-by-step explanation:

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ICE Princess25 [194]

Answer:D

Step-by-step explanation:

Radius=r=8

Φ=2π/3

π=180

2π=360

length of arc=Φ/360 x 2 x π x r

Length of arc=(2π/3 ➗ 2π) x 2 x π x 8

Length of arc=(2π/3 x 1/2π) x 2 x π x 8

Length of arc=((2πx1)/(3x2π)) x 2 x π x 8

Length of arc=2π/6π x 2 x π x 8

Length of arc=1/3 x 2 x π x 8

Length of arc=(1 x 2 x π x 8)/3

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7 0

2 years ago

The rectangle below has an area of x^2-15x+56x square meters and a length of x-7 meters.

Gennadij [26K]

$Heya \: \: ! \\ \\ \\ Area \: of \: rectangle \: = Length \: \times Width \\ \\ We \: are \: given \: that \: , \\ \\ Length \: = \: \: ( \: x - 7 \: ) \: metres \\ Area \: \: \: \: \: = \: \: \: ( \: {x}^{2} - 15x + 56 \: ) \: square \: meters \\ \\ Therefore \: \: , \: \\ {x}^{2} - 15x + 56 = ( \: x - 7) \times Width \\ \\ Width = \frac{ ({x}^{2} - 15x + 56 )}{(x - 7)} \\ \\ Width = \frac{(x - 7)(x - 8)}{(x - 7)} \\ \\ \\ Width = ( \: x - 8 \: ) \: \: m \: \: \: \: \: \: \: \: \: Ans.$