1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elena-2011 [213]
3 years ago
13

Mark placed a pool in his backyard, which is enclosed by a triangular fence. The radius of the pool is 20.5 feet How much of the

backyard is not covered by the pool? Use

Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

2644.415 feet spuared

Step-by-step explanation:

I think the attached photo is your full question, and my answer:

We need to find:

- the area of the  pool = π = 3.14*  = 1319.585 feet spuared.

- The area of the triangular fence = 1/2* 84*92 = 3964 feet spuared

So, the area of the backyard which is not covered by the pool is:

The area of the triangular fence - the area of the  pool

= 3964 - 1319.585

= 2644.415

Hope it will find you well.

You might be interested in
What is the value of the 4 in the number 546210​
love history [14]

Answer:

40,000

Step-by-step explanation:

refer to attached.

the number 4 is found in the Ten Thousands (10,000) place

hence the number 4 has the value of

4 x 10,000

= 40,000

4 0
3 years ago
Read 2 more answers
What is the distance in feet if you runs 8.05 kilometers every day?
Sveta_85 [38]
You run 26410.76 ft every day
8 0
4 years ago
I'll give you brainliest!!<br> How many inches are in feet?
kupik [55]

Answer:

12

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
For a population with an unknown distribution, the form of the sampling distribution of the sample mean is _____.a. exactly norm
maxonik [38]

Answer:

Approximately normal for large sample sizes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

The distribution is unknown, so the sampling distribution will only be approximately normal when n is at least 30.

So the correct answer should be:

Approximately normal for large sample sizes

7 0
4 years ago
Mark invests £2000 on an account that gives 4% compound interest.what will the value of his investment be after 6 years
I am Lyosha [343]

Answer: £2530.64

Step-by-step explanation:

The formula for calculating amount is given as :

A = P(1+r)^{n}

Where :

A = amount

P = principal

r = rate%

n = number of years

Substituting the values of each into the equation we have

A = 2000(1+0.04)^{6}

A = 2000 (1.04^{6})

A = 2530.638037

A ≈ £2530.64

8 0
3 years ago
Other questions:
  • Stefan is conducting an experiment to find the level of pollution in the air. He found that there are about 3 billion dust parti
    10·2 answers
  • Louis surveyed 50 people at a track meet to find out what their favorite events were. He found that 5 people like shot-put the b
    9·2 answers
  • Inverse fraction of f(x)=2x+1
    10·1 answer
  • A flagpole casts a shadow 20 ft long.
    5·2 answers
  • If a line of one billion people standing shoulder to shoulder stretches 395815 miles long what is the average shoulder width in
    9·1 answer
  • Solve for x given BD = 4x+3 and AE = 4x+8. Assume B is the midpoint of segment AC and D is the midpoint of segment CE.
    11·1 answer
  • solve |5x - 1| &lt; 1 a. {x|0 &lt; x &lt; 2/5} b. {x|x &lt; 0 or x &gt; 2/5} c. {x|-2/5 &lt; x &lt; 2/5}
    11·1 answer
  • 0.40 - 2.55<br> 5<br> please answer this
    10·1 answer
  • Logarithm
    7·1 answer
  • The coordinates of A,B,C are(6,3),(-3,5),(4,-2) respectively and P(x,y) is any point,prove that∆PBC/∆ABC=x+y-2/7​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!