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Elena-2011 [213]
3 years ago
13

Mark placed a pool in his backyard, which is enclosed by a triangular fence. The radius of the pool is 20.5 feet How much of the

backyard is not covered by the pool? Use

Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

2644.415 feet spuared

Step-by-step explanation:

I think the attached photo is your full question, and my answer:

We need to find:

- the area of the  pool = π = 3.14*  = 1319.585 feet spuared.

- The area of the triangular fence = 1/2* 84*92 = 3964 feet spuared

So, the area of the backyard which is not covered by the pool is:

The area of the triangular fence - the area of the  pool

= 3964 - 1319.585

= 2644.415

Hope it will find you well.

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stepladder [879]
10x + 2y = -2

2y = -10x -2

y = -5x - 1 (slope is -5 and a parallel line will have the same slope)


y = mx + b

slope(m) = -5

12 = -5(0) + b

12 = 0 + b

12 = b

so the parallel line is y = -5x + 12

hope this helps, God bless!

3 0
3 years ago
F divided by 28 equal 24
BabaBlast [244]
You can translate to:

F ÷ 28 = 24

F/28 = 24          Cross Multiply

F = 28 * 24

F = 672

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3 years ago
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If p(x) = 2x^3 - 3x + 5, what is the remainder of p(x) divided by (x - 5)
Alenkinab [10]

The question is

if p(x)= 2x³-3x+5, what is the remainder of p(x) divided by (x-5)

We use the synthetic division to find the remainder,

x-5=0

x=5

Now, write the coefficients of polynomial.


5 | 2  0  -3    5

   | ↓ 10  50  235

-------------------------------

     2 10  47  | 240→ is the remainder.

Quotient= 2x²+10x+47


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Show your work<br> −17x = −204
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Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B
Oksanka [162]

This is not the question, the correct question is:

A humanities professor assigns letter grades on a test according to the following scheme. A: Top 6% of scores B: Scores below the top 6% and above the bottom 59% C: Scores below the top 41% and above the bottom 17% D: Scores below the top 83% and above the bottom 7% F: Bottom 7% of scores.

Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B grade. Round your answers to the nearest whole number, if necessary.

Answer:  The numerical limits for grade B is 81 and 92

Step-by-step explanation:

Given that

mean Ж = 79

Standard deviation S = 8.4

B: Scores below the top 6% and above the bottom 59%

To find the numerical value for Grade B

Below the top bottom 6% ( 0.06) is

p ( X < Ж ) = 1 - 0.06

p ( X < Ж ) = 0.94

therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.94

(X - 79) / 8.4 = 1.5548 ( from normal distribution table )

X - 79 = 13.0603

X = 13.0603 + 79

X = 92.06 ≈ 92 ( nearest whole number)

Above bottom 59% ( 0.59) is

p ( X < Ж ) = 0.59

therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.59

(X - 79) / 8.4 = 0.2275 ( from normal distribution table )

X - 79 = 1.9114

X = 1.9114 + 79

X = 80.91 ≈ 81 ( nearest whole number)

So the numerical limits for grade B is 81 and 92

3 0
3 years ago
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