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chubhunter [2.5K]
2 years ago
13

Find f(-10) f(x)=7x-5​

Mathematics
2 answers:
Cloud [144]2 years ago
8 0

Answer:

Rewrite the equation in term of  

x

and  

y

.

f

(

x

)

=

2

x

2

−

7

x

+

5

Rewrite the equation in vertex form.

Tap for fewer steps...

Complete the square for  

2

x

2

−

7

x

+

5

.

Tap for more steps...

2

(

x

−

7

4

)

2

−

9

8

Set  

y

equal to the new right side.

y

=

2

(

x

−

7

4

)

2

−

9

8

Use the vertex form,  

y

=

a

(

x

−

h

)

2

+

k

, to determine the values of  

a

,  

h

, and  

k

.

a

=

2

h

=

7

4

k

=

−

9

8

Find the vertex  

(

h

,

k

)

.

(

7

4

,

−

9

8

)

Step-by-step explanation:

Inessa [10]2 years ago
6 0

Answer:

<h2>f(-10) = -75</h2>

Step-by-step explanation:

F(x) is simply another way of saying y. We are given the x value of -10. We can substitute this in for x and find y.

f(-10) = 7(-10) - 5

f(-10) = -70 - 5

f(-10) = -75

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If (a,b) is an ordered pair for x-y=5, is (b,a) also a solution?
alina1380 [7]
The answer is no. Because solution (a,b) means x=a, y=b.and we have a-b=5.  And (b,a) would mean x=b and y=a but then x-y=b-a=-(a-b)=-5≠5. So  the pair (b,a) is not a solution.


5 0
3 years ago
Solve the system below by elimination -2x-9y=-25
xz_007 [3.2K]
I think it’s 2x+9y-25=0
3 0
3 years ago
The following is the recipe to make one dozen muffins: 1 cups flour; 2 cups sugar; 2 tsps. Baking powder; 1 egg; 1 cup Crisco; 1
ivolga24 [154]

1.5 cups of flower, 3 cups sugar, 3 tbsp. baking powder, 1.5 eggs, 1.5 cups of Crisco, 1.5 cups of skim milk (hopefully not skin milk), and 1.5 cups of blueberries. Because 18 is 12 x 1.5 you just multiply all the given numbers by 1.5.

4 0
3 years ago
Please someone help me!!!!:)
Alla [95]

Answer:

275.4cm

Step-by-step explanation:

A = pi*r^2

r = 9

A = 3.14 * 9^2

A = 3.14 * 81

A = 275.4

Hope this helps!

5 0
2 years ago
Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. F(x) =
Troyanec [42]

Answer:

a) P (x <= 3 ) = 0.36

b) P ( 2.5 <= x <= 3  ) = 0.11

c) P (x > 3.5 ) = 1 - 0.49 = 0.51

d) x = 3.5355

e) f(x) = x / 12.5

f) E(X) = 3.3333

g) Var (X) = 13.8891  , s.d (X) = 3.7268

h) E[h(X)] = 2500

Step-by-step explanation:

Given:

The cdf is as follows:

                           F(x) = 0                  x < 0

                           F(x) = (x^2 / 25)     0 < x < 5

                           F(x) = 1                   x > 5

Find:

(a) Calculate P(X ≤ 3).

(b) Calculate P(2.5 ≤ X ≤ 3).

(c) Calculate P(X > 3.5).

(d) What is the median checkout duration ? [solve 0.5 = F()].

(e) Obtain the density function f(x). f(x) = F '(x) =

(f) Calculate E(X).

(g) Calculate V(X) and σx. V(X) = σx =

(h) If the borrower is charged an amount h(X) = X2 when checkout duration is X, compute the expected charge E[h(X)].

Solution:

a) Evaluate the cdf given with the limits 0 < x < 3.

So, P (x <= 3 ) = (x^2 / 25) | 0 to 3

     P (x <= 3 ) = (3^2 / 25)  - 0

     P (x <= 3 ) = 0.36

b) Evaluate the cdf given with the limits 2.5 < x < 3.

So, P ( 2.5 <= x <= 3 ) = (x^2 / 25) | 2.5 to 3

     P ( 2.5 <= x <= 3  ) = (3^2 / 25)  - (2.5^2 / 25)

     P ( 2.5 <= x <= 3  ) = 0.36 - 0.25 = 0.11

c) Evaluate the cdf given with the limits x > 3.5

So, P (x > 3.5 ) = 1 - P (x <= 3.5 )

     P (x > 3.5 ) = 1 - (3.5^2 / 25)  - 0

     P (x > 3.5 ) = 1 - 0.49 = 0.51

d) The median checkout for the duration that is 50% of the probability:

So, P( x < a ) = 0.5

      (x^2 / 25) = 0.5

       x^2 = 12.5

      x = 3.5355

e) The probability density function can be evaluated by taking the derivative of the cdf as follows:

       pdf f(x) = d(F(x)) / dx = x / 12.5

f) The expected value of X can be evaluated by the following formula from limits - ∞ to +∞:

         E(X) = integral ( x . f(x)).dx          limits: - ∞ to +∞

         E(X) = integral ( x^2 / 12.5)    

         E(X) = x^3 / 37.5                    limits: 0 to 5

         E(X) = 5^3 / 37.5 = 3.3333

g) The variance of X can be evaluated by the following formula from limits - ∞ to +∞:

         Var(X) = integral ( x^2 . f(x)).dx - (E(X))^2          limits: - ∞ to +∞

         Var(X) = integral ( x^3 / 12.5).dx - (E(X))^2    

         Var(X) = x^4 / 50 | - (3.3333)^2                         limits: 0 to 5

         Var(X) = 5^4 / 50 - (3.3333)^2 = 13.8891

         s.d(X) = sqrt (Var(X)) = sqrt (13.8891) = 3.7268

h) Find the expected charge E[h(X)] , where h(X) is given by:

          h(x) = (f(x))^2 = x^2 / 156.25

  The expected value of h(X) can be evaluated by the following formula from limits - ∞ to +∞:

         E(h(X))) = integral ( x . h(x) ).dx          limits: - ∞ to +∞

         E(h(X))) = integral ( x^3 / 156.25)    

         E(h(X))) = x^4 / 156.25                       limits: 0 to 25

         E(h(X))) = 25^4 / 156.25 = 2500

8 0
3 years ago
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