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3 years ago

Quis mode Easyhasil dariT²⁵⁴÷T²⁴³=

Mathematics

1 answer:

Natasha2012 [34]3 years ago

7 0

Answer:

T²⁵⁴÷T²⁴³=

T²⁵⁴-²⁴³=

=T¹¹

done and thank you

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Jean my action is selling jeans at a 15% off the regular price the regular price is 25.00 per pair what is the sale price of the

sergij07 [2.7K]

Answer:

$21.25

Step-by-step explanation:

25 decrease 15% =

25 × (1 - 15%) = 25 × (1 - 0.15) = 21.25

8 0

3 years ago

43/982=?<br> what does ? =

rodikova [14]

Answer:

43/982 = 0.043788187372708757637474541751527494908350305498981670061...

Step-by-step explanation:

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3 years ago

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Solve each system by graphing.

Helen [10]

They intersect at point...

(-1,4)

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3 years ago

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A total of 20 quarters and nickels add up to $4.00. How many nickels are there?

mariarad [96]

Answer:

5 nickels

Step-by-step explanation:

You can setup and solve a system of equations, or you can solve by trial and error until you get the correct answer.

Here is the solution by trial and error.

If all 20 coins are quarters, the value is 20 * $0.25 = $5

That is too much value.

Let's try 16 quarters. 16 quarters are worth 16 * $0.25 = $4.

That is the correct value, but it is only with quarters, and only 16 of them.

We need fewer quarters than 16.

Try 12 quarters: 12 * $0.25 = $3.00

The number of nickels is: 20 - 12 = 8

8 nickels are worth 8 * $0.05 = $0.40

12 quarters and 8 nickels are worth $3.00 + $0.40 = $3.40

There are 20 coins, but the value is too low.

The number of quarters is between 12 and 16.

Try 14 quarters and 6 nickels:

14 * $0.25 + 6 * $0.05 = $3.50 + $0.30 = $3.80

We are closer to $4 but not there yet.

Try 15 quarters and 5 nickels.

15 * $0.25 + 5 * $0.05 = $3.75 + $0.25 = $4

The total value is $4 and there are 20 coins. This is the answer.

15 quarters and 5 nickels works.

Answer: 5 nickels

8 0

3 years ago

I need help with this question

bearhunter [10]

Answer:

7.28 miles

Step-by-step explanation:

Suppose the distance at closest approach is represented by x. Then the distance to the point of closest approach at the first sighting is ...

d1 = x·tan(62°)

At the second sighting, the distance to the point of closest approach is ...

d2 = x·tan(38°)

The difference of these distances is 8 miles, so we have ...

d1 -d2 = 8 = x(tan(62°) -tan(38°))

Dividing by the coefficient of x, we find ...

x = 8/(tan(62°) -tan(38°)) ≈ 7.2764 . . . . miles

The point of closest approach is about 7.28 miles from the landmark.

5 0

3 years ago

Quis mode Easyhasil dariT²⁵⁴÷T²⁴³=​

Quis mode Easyhasil dariT²⁵⁴÷T²⁴³=