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padilas [110]
3 years ago
6

Hi guys please help me!! I kinda need this thank yu so much!!

Mathematics
2 answers:
Basile [38]3 years ago
6 0

Answer:

188.496

Step-by-step explanation:

A=2πrh+2πr^2=

A=2·π·3·7+2·π·3^2

A= 188.49556

Rounded up because 4th decimal is a 5.

A= 188.496

BlackZzzverrR [31]3 years ago
4 0

Answer:

I don't know if it is correct but if not you can ask other ty

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An equiangular triangle has one side of length six inches. What is the height of the triangle, drawn from that side, to the near
Mandarinka [93]

9514 1404 393

Answer:

  5.2 in

Step-by-step explanation:

An equiangular triangle is also equilateral. All sides will be 6 inches, and the height line will be a perpendicular bisector of the side.

Using trig, the height is ...

  (3 in)tan(60°) = 3√3 in ≈ 5.2 in

Using the Pythagorean theorem, ...

  h² = 6² -3² = 27

  h = √27 ≈ 5.2 . . . inches

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3 years ago
I need getting A. That is the only thing u am struggling with.
IrinaVladis [17]
The answer your looking for well be A
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3 years ago
Can y’all help me on num 3
ololo11 [35]

Answer:

-8 degrees

Step-by-step explanation:

-4 minus 7 degrees add 3 degrees

4 0
4 years ago
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3 years ago
The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor
nadya68 [22]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can use as an estimator for p \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

3 0
3 years ago
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