The maximum height is 124 inches and it happens at 4 seconds
Answer:
25%
Step-by-step explanation:
let length of 1st square be x and second be y
then
A/q
x = y/2
area of first square = x^2 = (y/2)^2 = (y^2)/4
and
area of second square = y^ 2
so from sbove two lines
area of first square = 1/4 * area of second square
= 1/4 *100%
so..
area of first sqare = 25% of area of second square
Part A
Given that

Then,

For

, then

Thus,

For

, we have

Part B
Recall that from part A,

Now, at initial position, t = 0 and

, thus we have

and when the velocity drops to half its value,

and

Thus,

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by
Answer:
(5,-6)
Step-by-step explanation:
ONE WAY:
If
, then
.
Let's simplify that.
Distribute with
:

Combine the end like terms
:

Use
identity for
:

Combine like terms
and
:

We are given
.
So we have that
.
The vertex happens at
.
Compare
to
to determine
.



Let's plug it in.




So the
coordinate is 5.
Let's find the corresponding
coordinate by evaluating our expression named
at
:




So the ordered pair of the vertex is (5,-6).
ANOTHER WAY:
The vertex form of a quadratic is
where the vertex is
.
Let's put
into this form.
We are given
.
We will need to complete the square.
I like to use the identity
.
So If you add something in, you will have to take it out (and vice versa).





So we have in vertex form
is:
.
The vertex is (3,-6).
So if we are dealing with the function
.
This means we are going to move the vertex of
right 2 units to figure out the vertex of
which puts us at (3+2,-6)=(5,-6).
The
coordinate was not effected here because we were only moving horizontally not up/down.
Answer:
center at (6, -4) r = √7
Step-by-step explanation:
(x – 6)^2 + (y + 4)^2 = 7
This is in the form
(x – h)^2 + (y - k)^2 = r^2
Where (h,k) is the center of the circle and r is the radius of the circle
Rearranging the equation to match this form
(x – 6)^2 + (y -- 4)^2 = sqrt(7) ^2
The center is at (6, -4) and the radius is the sqrt(7)