Can y’all help me on num 3
2 answers:
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Answer:
follow the statement below
Step-by-step explanation:
The question you presented here has multiple (un-limited) solutions unless you have another condition to solve for a single solution.
Equation: y = ax² + bx + c
y intercept (0 , 3): c = 3
axis of symmetry x=-5, therefore a corresponding point (-10,3) on the curve
3 = a*(-10)² + b*(-10) + 3
100a - 10b = 0
b = 10a .... any pair like a=0.5 b=5; a=1 b=10 0r a=2 b=20 ..... all fit the function
y = 0.5x² + 5x +3
y = x² + 10x + 3
y = 2x² + 20x +3
........................
Answer:
From five given points it is find that points (1 , 1) and (4 , -1) will apply
Step-by-step explanation:
According to question,
Slop of line (m) =
And y-intercept is ( 0, )
So from above slope and points, the equation of line can be written as
y = mx + c
i.e =
x + c
=
(0) + c
= 0 + c
Or, c =
A) With points ( 5, )
At x = 5, y = (5) +
or, y = +
so, y =
Hence this points do not apply
B) With points ( 1 , 1 )
At x = 1, y = (1) +
or, y =
So, y =
y = 1
Hence this points will apply
C) With points ( 4 , -1 )
At x = 4 , y = (4) +
y =
y =
So, y= -1
Hence this points will apply
D) With points (-3 ,7)
At x = - 3, y = (-3) +
y =
Hence this point will not apply
E) with points (0 , 0)
At x 0, y = (0) +
Or, y = 0 +
y =
Hence this point will not apply
∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply
Answer