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3 years ago

Helppppppppppppppppppppppppppppppppppppppppppppppppp i will put brainiest

Mathematics

1 answer:

baherus [9]3 years ago

6 0

a) can't be divided into equal sections of this length

b) ""

c) ""

d) ""

11.4 is not divisible by any of these lengths.

???

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The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope

lesya692 [45]

(1) D

$L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt$

Integrate by parts, taking

$u = t \implies \mathrm du=\mathrm dt$

$\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}$

Then

$L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}$

(2) A

$L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}$

7 0

3 years ago

If x = 2 + V3, then the value of (x + 1/x) is

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given

x + $\frac{1}{x}$ ← substitute x = 2 + $\sqrt{3}$

= 2 + $\sqrt{3}$ + $\frac{1}{2+\sqrt{3} }$

Rationalise the denominator of the fraction by multiplying the numerator/ denominator by the conjugate of the denominator.

The conjugate of 2 + $\sqrt{3}$ is 2 - $\sqrt{3}$ , thus

= 2 + $\sqrt{3}$ + $\frac{2-\sqrt{3} }{(2+\sqrt{3} )(2-\sqrt{3}) }$

= 2 + $\sqrt{3}$ + $\frac{2-\sqrt{3} }{4-3}$

= 2 + $\sqrt{3}$ + 2 - $\sqrt{3}$

= 4

6 0

3 years ago

Help plz it is so ahrd

-BARSIC- [3]

I think it’s 300 the answer

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4 years ago

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What is absolute value and why is it always positive?

xxMikexx [17]

Answer:

Step-by-step explanation:

An absolute value is the distance a number is from 0 on the number line. So, regardless if it is a negative or a positive number, the distance from that number to 0 will always be positive. For example, -5 is 5 units away from 0, and 5 is also 5 units from zero. They have the same absolute value, even though one is negative and the other is positive.

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3 years ago

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Find an equivalent ratio in simplest terms:<br> 54 : 70

Elena L [17]

Answer:

27/35.

I can break it down for you to understand if u want.

Step-by-step explanation:

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3 years ago

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