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Scilla [17]
3 years ago
11

G(x) = 4x -9, what is g^-1(x)

Mathematics
1 answer:
Ivenika [448]3 years ago
5 0

Answer:

g^-1(x)= 1/4x-9

1 is above 4x-9

Step-by-step explanation:

g(x)= 4x-9

and g^-1 = 1/g(x)

so:

1/gx=1/4x-9

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