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2 years ago

How to solve 1/3+1/x=1/5

Mathematics

1 answer:

DENIUS [597]2 years ago

4 0

1/x=1/5-1/3

1/x=-2/15

X= -15/2

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Consider this quadratic equation. x^2+2x+7=21 The number of positive solutions to this equation is ____. The approximate value o

babunello [35]

Answer:

Step-by-step explanation:

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2 years ago

Find the length BC

Nady [450]

Answer:

The length of BC = 12

Step-by-step explanation:

c^2 = a^2 + b^2

15^2 = 9^2 + b^2

225 = 81 + b^2

b^2 = 225 - 81

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3 years ago

-8n+4(1+5n)=-6n-14 show your work

dmitriy555 [2]

Answer:

n = -1

Step-by-step explanation:

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2 years ago

jasenka [17]

Answer:

oops! it's too hard!!

i think i should need to do first so that i could provide you correct answer of it!!

5 0

2 years ago

If a triangle is 12 inches high and has a 20 inch long hypotenuse then how wide is it?

Ber [7]

Answer:

The triangle should be 16 inches wide.

Step-by-step explanation:

$\text {Use the Pythagorean Theorem to solve for the leg.}\\a^2 + b^2 =c^2$

What we know:

One of the legs measures 12 inches.

The hypotenuse is 20 inches.

We need to solve for b. Solving for a while b is 12 would also be acceptable.

$12^2 + b^2 = 20^2 \text { OR } a^2 +12^2=20^2$

We will use the first equation.

$12^2 + b^2 = 20^2\\12 * 12 = 144\\20 * 20 = 400\\\\\boxed {144 + b^2 = 400}$

$\text {Subtraction property of equality: }\\144-144+ b^2 = 400-144\\\boxed {b^2 = 256}\\\\\text {Take the square root of 256: }\\\sqrt{256}=\sqrt{b^2} \boxed {16 = b}$

The triangle should be 16 inches wide.

3 0

3 years ago