2 cakes - Theresa's and Joe's
Theresa's cake had 6 pieces after she cut it. (2 times the size of Joe's pieces)
Joe's cake had 12 pieces after he cut it. (1/2 the size of Theresa's pieces)
We know that 8/12ths of ONE cake were eaten and that Joe ate 2 of his pieces.
We want to know how many pieces Theresa ate of her cake. Keeping in mind that her pieces are equal to 2 of Joe's pieces we can solve this question.
8/12 eaten total
if 2/12 by Joe
then 8-2 = 6, 6/12 by Theresa
(BUT: Theresa's pieces were twice the size of Joe's so we will divide by 2)
6/12 = 3/6
Answer: Theresa ate 3 pieces of her cake
Answer:
Step-by-step explanation:
Given
Required
Determine the distance between the two points
Distance (D) is calculated as:
Substitute values for x's and y's
Express as 9 * 2
Split:
<span>Ok. You would set up the problem like this: 32/x=64/100 and then cross multiply; 3200=64x; divide both sides by 64; x=50. Mary has 50 customers.</span>
Answer:
A: 22
Step-by-step explanation:
2The interquartile range begins at 45 and ends at 67. All you need to do is subtract 45 drom 67, and you get 22.
y =x+10
y =6x+30
substitute x+10 into the 2nd equation anywhere you see y
x+10 = 6x+30
subtract x from each side
x-x+10 = 6x-x+30
10 = 5x+30
subtract 30 from each side
10-30=5x+30-30
-20 = 5x
divide by 5 on each side
-20/5 =5x/5
-4=x
now solve for y
y=x+10
y = -4 +10
y=6
Answer: x=-4
y=6
or (-4,6)
3. y = -3x-6
6x+5y=-30
6x+5(-3x-6) =-30
5x-15x-30=-30
-20x-30=-30
-20x=0
x=0
y = -3x-6
y=-6
