It will be the last one a×b×b
Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:
<h3>What is the trigonometric identity using in this problem?</h3>
The identity that relates the sine squared and the cosine squared of the angle, as follows:

In this problem, we have that the sine is given by:

Hence, applying the identity, the cosine is given as follows:






The tangent is given by the sine divided by the cosine, hence:




More can be learned about trigonometric identities at brainly.com/question/24496175
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Answer:
-1/2
Step-by-step explanation:
Answer:
6.14125(0.15) = 0.9211875 (below 1)
6.14125 - 0.92118 = 5.22007
Step-by-step explanation:
Given data
1. 10(.15)=1.5
2. 10-1.5=8.5
3. 8.5 (.15)=1.275
4. 8.5-1.275=7.225
continuation the sequence
5) 7.225 (0.15) = 1.08375
6) 7.225 - 1.08375 = 6.14125
7) <u> 6.14125(0.15) = 0.9211875 (below -one)</u>
8 ) <u> 6.14125 - 0.9211875 = 5.2200625 (get number 5)</u>
9) 5.2200625(0.15) = 0.783009
10) 5.2200625 - 0.783009 = 4.4370532