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icang [17]
2 years ago
6

Nick’s house is between his school and the library, which are one mile apart on the same street. A mile is 5280 feet. After scho

ol, Nick walks 3195 feet to his house. How many more feet he need to walk to get to the library?
Mathematics
1 answer:
Montano1993 [528]2 years ago
7 0

Nick's needs to walk 2,085 feet more to get to the library.

Given:

<em>1 mile</em> = 5,280 feet

Distance from Nick's school to his house = 3195 feet

Recall,

Nick’s house is between his school and the library, which is one mile apart

So,

<em>Distance to work to the library from Nick's house = 1 mile - Distance from Nick's school to his house</em>

= 5,280 feet - 3,195 feet

= 2,085 feet

Therefore,

Nick's needs to walk 2,085 feet more to get to the library.

Read more:

brainly.com/question/20365394

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Use the image to match the arc/angle measure.
IrinaK [193]

Answer:

The following measurements are:

m\angle{STR}=23^\circ (Option #4)

m{QT}=142^\circ (Option #7)

mST=134^\circ (Option #5)

mRQ=38^\circ (Option #2)

Step-by-step explanation:

To begin, we can find the measure of \angle{STR} by applying the inscribed angle theorem: an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

Since the intercepted arc (RS) is 46 degrees, we have:

46=2\theta\\23=\theta

Next, we can find the measure of arc QT using the same theorem. So,

QT=2(71)\\QT=142

Notice that the chord RT is actually a diameter. From the theorem about the inscribed angle including a diameter, we know that the intercepted arc will have a measure of 180^\circ. Since the arc ST is part of the arc RST, and we know RS is 46^\circ, we can set up and solve this equation:

RST = RS + ST\\180 = 46 + ST\\134 = ST

We can use the same idea to find RQ. We know that RQT is 180^\circ and QT is 142^\circ, so:

RQT = RQ + QT\\180 = RQ + 142\\38 = RQ

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Question 5 of 10
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a

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