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dybincka [34]
3 years ago
14

HELP PLSSSSSSSSSSSSSSSSSSSS

Mathematics
2 answers:
navik [9.2K]3 years ago
8 0

Step-by-step explanation:

I need help in that too :(

emmainna [20.7K]3 years ago
4 0

Answer:

1 true

2true

3 false

4 false

Step-by-step explanation:

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Tickets at the carnival cost 35 each.on Friday night the carnivals earned a total of 12,425 in ticket sales on Saturday night th
Blababa [14]

ticket sale on Saturday night is triple the ticket sale on Friday night.

Therefore

ticket sales on Saturday night = 3 x 12425 = 37275

Then

ticket sales for both nights = 12425 + 37275 = 49700

A ticket costs 35.

Let the number of people that attended the carnival on both nights be n.

Then, we have

\begin{gathered} 35n=49700 \\ \Rightarrow n=\frac{49700}{35}=1420 \end{gathered}

Therefore 1420 people attended the carnival on both nights

6 0
1 year ago
What is 5/12 divided by 3/16 as a fraction?
GuDViN [60]
<span>The answer is
= 20/9
=2 2/9</span>
8 0
3 years ago
Read 2 more answers
Solve by completing the square.
Leona [35]

Answer:

28- 4±\sqrt{21}

30- -4±2i

Hope this helps!

3 0
2 years ago
Distribute and combine like terms. Please show all of your work.<br><br> -5(3x + 7) - 4(x - 4) + 11
Varvara68 [4.7K]

For this case we have the following expression:

-5 (3x + 7) -4 (x-4) +11

For simplicity we follow the steps:

We apply distributive property to the terms within the parenthesis, bearing in mind that:

- * + = -\\- * - = +\\-15x-35-4x + 16 + 11 =

We add similar terms taking into account that equal signs are added and the same sign is placed, while different signs are subtracted and the sign of the major is placed.

-15x-4x-35 + 16 + 11 =\\-19x-8

ANswer:

-19x-8

5 0
3 years ago
Read 2 more answers
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
3 years ago
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