2 years ago

12q - 6 + 7 - 3q + q

1 answer:

3 0

Answer:

10q - 1

Step-by-step explanation:

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Black_prince [1.1K]

Find the quotient: (25c^4 + 20c^3) ÷ 5c5c^3+4c^2.

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netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

 $|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}$

Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.

$|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5$

$|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6$

$|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4$

$|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \ \sqrt{25}=5$

$|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4$

Answer: B and D

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3 years ago

attashe74 [19]

It should be one hundred twenty six (126) if my math is correct

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3 years ago

Alexxx [7]

2.25 but i am not sure i hope that helps

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3 years ago

Rasek [7]

Answer:

choice 2) 4/3πr³

Step-by-step explanation:

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2 years ago