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ratelena [41]
3 years ago
13

Given the congruent figures solve for the missing variable

Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0
 I don't see the question...is that my problem?  Or am I not doing things right?
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Find the area A of polygon CDEFGH with the given vertices. C(0,5), D(2,5), E(2,3), F(3,2), G(-1,2), H(0,3)
enot [183]

Answer:

<em>The area of the polygon CDEFGH is 7</em>

Step-by-step explanation:

<u>Area of a Polygon</u>

The area of a polygon is generally calculated as the sum of the smaller areas that form its full shape, give each partial area has a known shape, like a square, rectangle, triangle, circle, etc.

The six points given in the question are plotted in the image below. They form a polygon whose area can be divided into two smaller shapes:

The area CDHE is a square of length side 2. Area of a square:

A1=L^2

The area HEFG is a trapezoid with bases lengths 4 and 2,  and height 1. Area of a trapezoid:

\displaystyle A2=\frac{b1+b2}{2}h

Calculate both areas:

A1=2^2=4

\displaystyle A2=\frac{2+4}{2}\cdot 1=3

Total Area=4+3=7

The area of the polygon CDEFGH is 7

8 0
3 years ago
Is 5.421 greater or less then 5.4
zavuch27 [327]
Greater than 5.4 i hate the 20 characters rule
5 0
3 years ago
Read 2 more answers
Which pair of line segments are perpendicular in a quadrilateral
Gnesinka [82]
A quadtriatel is said to contain perpendicular diagnols if four go 90 degree angles are formed at the intersection of these lines
8 0
3 years ago
riel wants to use squares to tile a floor that measures 240 cm by 300 cm what is the length of the largest square he can use
Alexxx [7]
<span>So, what you want is the biggest square that can evenly tile a space 240*300. The biggest possible number that can divide 240 and 300. Does that ring any bells? Maybe you should divide 240 and 300</span>
4 0
3 years ago
PLEASE HELP!!!!! What is the value of x in the matrix equation below?
Brums [2.3K]

The given matrix equation is,

1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right].

Multiplying the matrices with the scalars, the given equation becomes,

\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Adding the matrices,

\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right]  =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Matrix equality gives,

1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2

Solving the equations together,

y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10

We can see that the equations are not consistent.

There is no solution.

3 0
3 years ago
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