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3 years ago

If x^2 = 10, what is the value of x?

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

7 0

X^2 = 10
square both sides, so you get x = the square root of 10.
so x = the square root of 10

maw [93]3 years ago

4 0

X^2=10
x=3.16 (3sig.figs)

Hope this helps :)

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Dakota and Christine went shopping. Dakota bought two scarves and one hat for $13 Christine bought one scarves and two hats for

White raven [17]

One scarf=s
One hat=h

2s+h=13
s+2h=14

h=13-2s
(plug that into the other equation)

s+2(13-2s)=14
s+26-4s=14
26-3s=14
-3s=-12
s=4

One hat=$5
One scarf=$4
5+4=9
Price of one hat AND one scarf is $9

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Step-by-step explanation:

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3 years ago

Find the area of the shaded region in square units. Show your reasoning.

motikmotik

Answer:

40 square units

Step-by-step explanation:

First of all, lets say that square has side $l$ , so, the area unit is $l^2$

the diagonal's square is $l\sqrt{2}$

CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)

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3 0

3 years ago

The sum of three consecutive odd numbers is 123 what is the smallest of the three numbers

Inga [223]

Answer:

Step-by-step explanation:

Let the three consecutive odd numbers be:

x+2, x+4, x+6.

The sum of the consecutive numbers is 123 i.e

x+2 + (x+4) + (x+6) = 123

x + 2 + x + 4 + x + 6 = 123

3x + 12 = 123

Collect like terms

3x = 123 — 12

3x = 111

Divide both side by the coefficient of x i.e 3

x = 111/3

x = 37

Now let us find the value of the three odd numbers. This is illustrated:

1st : x + 2 = 37 + 2 = 39

2nd : x + 4 = 37 + 4 = 41

3rd : x + 6 = 37 + 6 = 43

The smallest of the three consecutive odd numbers is 39

5 0

3 years ago

Solve by substitution <br> X^2= 2y + 10<br> 3x-y = 9

Viefleur [7K]

Answer:

$x=-4\\ x=-2\\ y=-21\\ y=-15$

Step-by-step explanation:

$x^{2} =2y+10$

$y=-9+3x$

$x^{2} =2(-9+3x)+10$

$x^{2} =-18+6x+10$

$x^{2} =6x-8$

$x^{2} -6x+8$

$x=-4, -2$

$y=-9+3(-4)$

$y=-9-12$

$y=-21$

$y=-9+3(-2)$

$y=-9-6$

$y=-15$

8 0

3 years ago

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