May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer: Quedarían nueve
Step-by-step explanation:
Answer:-5
Step-by-step explanation:
Answer:It's an arithmetic sequence with a common difference, d, = 4
A1 = 8
A2 = 8+4 = 12
A3 = 12+4 = 16 = 8+4(3-1) = 8+4(2) = 8+8
AN = A1 + d(N-1)
AN = 8 +4(N-1) = the Nth term in the sequence
Step-by-step explanation: hoped it helped
