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eduard
3 years ago
13

(x-8)x(-7x-17) - simplify

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

-7x^3+39x^2+136x

Step-by-step explanation:

= x(x-8) (-7x - 17)

( x - 8 ) ( -7 x - 17) : -7x^2 + 39x+136

= x( -7x^2 + 39x + 136)

= x( -7x^2) + x * 39x * 136

= -7x^3 + 39x^2 + 136x

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I need help please?!!!!
Nata [24]
You would simply add the 54 to the -12 and get +42
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3 years ago
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out of 45 times at bat, Raul got 19 hits find Ralph's batting average rounded to the nearest thousandth
Aleksandr-060686 [28]
Batting average = hits/total = 19/45 = 0.422
7 0
3 years ago
4x - y = 3<br> The coordinate points for that equation
zlopas [31]

Answer:

Step-by-step explanation:

4x - y = 3

add Y to both sides

4x = 3 + y

minus 3 from both sides

y = 4x - 3

5 0
4 years ago
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The sum of three numbers is 102. The first number is 6 more than the second. The third number is 4 times the second. What are th
const2013 [10]

Answer:

1st number: 22

2nd number: 16

3rd number: 64

Step-by-step explanation:

x + y + z = 102

x = 6 + y

z = 4y

plug that in!

(6 + y) + y + (4y) = 102

get rid of the parenthesis (I added them so you could see what I was replacing) and add like terms.

6 + 6y = 102

move 6 to the other side.

6y = 96

y = 16

now that you know one number, you can solve the equations for the rest!

x = 6 + (16)

z = 4(16)

__________________________________________________________

x = 22

y = 16

z = 64

6 0
3 years ago
A particle moves in a straight line so that its velocity at time
riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.  

s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75

Now we can use this value of t to formulate the position function s(t):

s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\

this is the position at time t.

to find the position at t=2

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{31}{4} = 7.75

the position of the particle at time, t =2 is s(2) = 7.75

3 0
4 years ago
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