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eduard
2 years ago
13

(x-8)x(-7x-17) - simplify

Mathematics
1 answer:
xenn [34]2 years ago
7 0

Answer:

-7x^3+39x^2+136x

Step-by-step explanation:

= x(x-8) (-7x - 17)

( x - 8 ) ( -7 x - 17) : -7x^2 + 39x+136

= x( -7x^2 + 39x + 136)

= x( -7x^2) + x * 39x * 136

= -7x^3 + 39x^2 + 136x

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What is (x+2)(x+5) in polynomial standard form
Harlamova29_29 [7]

Answer:

=x^2+7x+10

Step-by-step explanation:

Simplify: xx+5x+2x+2.5: x+7x+10

Add similar elements: 5x+2x= 7x

=xx+7x+2.5

xx=x2

2.5=10

=x+7x+10

Answer: =x^2+7x+10

<em><u>Hope this helps.</u></em>

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3 years ago
What is the value of the expression 4 Superscript 4?
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Answer:

What is the value of the expression 4 Superscript 4?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
X/3 +11=1/15 solve the following equation
fenix001 [56]
<span>here is what i get :
x/3+11-(1/15)=0 </span>
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3 years ago
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Annie's great-grandparents lived in a log cabin with their 3 children. The log cabin had a floor area of 450 square feet. The ce
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Answer:

you would have to multiply 450•7

4 0
3 years ago
Compare the process of solving |x – 1| + 1 &lt; 15 to that of solving |x – 1| + 1 &gt; 15. Check all of the following you includ
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The required Comparison of the inequalities are

  • The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.

The range of values encompassing the region's junction is (-13, 15).

  • If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.

<h3>What is inequality?</h3>

When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.

We take into account the various variables of the inequality

|x – 1| + 1 > 15

Therefore

|-x-1|+1-1<15-1

|-x-1|-1 <14

13<x<15

The required region lies between the inequality -13 <x< 15.

Simplify the inequality Ix-11+1 > 15 we get,

|x-1|+1 > 15

|x+1| +1-1 >15-1

|x-1| > 14

x> 15  

x<-13

  • If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
  • If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.

Read more about inequalities

brainly.com/question/20383699

#SPJ1

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2 years ago
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