PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
Jenny average swimming speed was 2.5 km/h, her average biking speed was 24 km/h and her average running speed was 12 km/h.
<h3>Speed</h3>
Speed is the ratio of total distance travelled to total time taken. It is given by:
Speed = distance / time
Let a represent the average swimming speed, b the average biking speed and c the average running speed.
Her average biking speed was 2 times her average running speed, hence:
Her average running speed was 8 times her average swimming speed. Hence:
Total distance of the triathlon was 55.5 kilometers. Hence:
a * 1 hour + b * 1.75 hour + c * 1 hour = 55.5 (3)
From equation 1, 2 and 3:
a = 2.5, b = 24, c = 12
Jenny average swimming speed was 2.5 km/h, her average biking speed was 24 km/h and her average running speed was 12 km/h.
Find out more on speed at: brainly.com/question/6504879
Answer:
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Answer:
see explanation
Step-by-step explanation:
In an arithmetic sequence the common difference d is
d = a₂ - a₁ = 10 - 8 = 2
To obtain the next term in the sequence add d to the previous term, that is
a₅ = 14 + 2 = 16
a₆ = 16 + 2 = 18
a₇ = 18 + 2 = 20
The next 3 terms in the sequence are 16, 18, 20
The n th term equation for an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 8 and d = 2, thus
= 8 + 2(n - 1) = 8 + 2n - 2 = 2n + 6
