Ask question

Ask question

All categories

3 years ago

6

en la feria del condado, la calabaza con la cinta roja pesaba 108 libras menos que la calabaza con la cinta azul. cuanto pesaba

la calabaza con la cinta azul?

1 answer:

kvasek [131]3 years ago

5 0

Answer:

sorry i dont know

Step-by-step explanation:

You might be interested in

What would this question look like after we change the mixed number to improper & use KCF to rewrite the question?

iris [78.8K]

Answer:

The question $3\frac{1}{2}\div\frac{1}{3}$ after change the mixed number to improper & using KCF will become : $\mathbf{=\frac{7}{2}\times \frac{3}{1}}$

Option B is correct option.

Step-by-step explanation:

We need to change the mixed number to improper & use KCF to rewrite the question.

The expression is: $3\frac{1}{2}\div\frac{1}{3}$

First converting mixed fraction into improper fraction

Multiply whole number with the denominator i,e (3*2=6) now add the numerator i.e (6+1) = 7/2

Solving:

$3\frac{1}{2}\div\frac{1}{3}\\=\frac{7}{2}\div\frac{1}{3}$

Using KCF

KCF stands fro Keep it, Change it, Flip it.

It is used when division sign is converted to multiplication the term (1/3) is reversed to (3/1)

So, our expression will be

$=\frac{7}{2}\times \frac{3}{1}$

So, The question $3\frac{1}{2}\div\frac{1}{3}$ after change the mixed number to improper & using KCF will become : $\mathbf{=\frac{7}{2}\times \frac{3}{1}}$

Option B is correct option.

5 0

3 years ago

Set Hill 1 to 75 cm and the other hills to 0 cm. What is the height in meters?

yanalaym [24]

Cm to meter is divided by 100 so, 75 is divided by 200 is equals to 0.75 meters

8 0

3 years ago

A box is 12 in, high, 24 in. long, and 8 in. wide. What is the longest poster you could fit in

never [62]

Answer:

If you put the posters in the box diagonally from bottom corner to the top corner. It will fit a poster 26 in long.

x = SqRoot (24^2 + 12^2)= 26.83 in

One one will fit because it has to go right into each of the corners to fit in the box.

Step-by-step explanation:

7 0

3 years ago

Please help! 20 points thanks :)

4vir4ik [10]

Answer:

Option A

Step-by-step explanation:

We use the slope formula:

$\frac{y_{2}-{y_{1}} }{x_{2} -x_{1} }$

We substitute the values given and see which option corresponds with our equation:

$\frac{-4-(-6)}{-2-3}$
Option A must be correct

5 0

3 years ago

Read 2 more answers

If alpha and beta are the roots of a quadratic polynomial 3x^2-6x-1 find the values of (Alpha-beta)

Murrr4er [49]

Answer:

Either $-4\sqrt{6}$ or $4\sqrt{6}$ , depending on whether $\alpha$ is larger than $\beta$ .

Step-by-step explanation:

The two roots (might necessarily be distinct or real) of the quadratic equation

$ax^{2} + bx + c = 0$ , where $a$ , $b$ , and $c$ are constants and $a\ne 0$ are

$\displaystyle x_1 = \frac{-b+\sqrt{\text{b^{2} - 4ac}}}{2a}$ , and
$\displaystyle x_2 = \frac{-b-\sqrt{\text{b^{2} - 4ac}}}{2a}$ .

The difference between the two will be either:

$x_1 - x_2 = 2\sqrt{b^{2} - 4ac}$ or

$x_2 - x_1 = -2\sqrt{b^{2} - 4ac}$ .

For this question,

$a = 3$ ,
$b = -6$ , and
$c = -1$ .

$x_1 - x_2 = 2\sqrt{(-6)^{2} - 4\times 3\times (-1)} = 4\sqrt{6}$ , or

$x_1 - x_2 = -2\sqrt{(-6)^{2} - 4\times 3\times (-1)} = -4\sqrt{6}$ .

7 0

3 years ago