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Mumz [18]
3 years ago
5

?????????????????? ??????????????????

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
7 0

See attached file for the answer! Please mark brainliest!

Black_prince [1.1K]3 years ago
5 0

Gw kangen sama Clarisssa hikshiks

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I need 11 and 12 thanks!
adelina 88 [10]

Answer:

11. c > 5

12. option 1

Step-by-step explanation:

5 0
3 years ago
A quarter of the sum of a number and 20 is equivalent to 30. Find the number.
Alisiya [41]

Answer:

X = 100

Step-by-step explanation:

X + 20 over 4 = 30

1/4x + 5 = 30

-5               -5

1/4x = 25

multiply both sides by 4

x = 100

4 0
4 years ago
If x^2=40, what is the value of x?
Ainat [17]

if x^2=40 you would need to square root both sides to get x alone therefore x=6.3

5 0
3 years ago
Read 2 more answers
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
igor_vitrenko [27]

Answer:

b. The vertical asymptote does not change, the horizontal asymptote changes to y= -7

Step-by-step explanation:

k = -7 is a vertical shift of -7

in the transformation

g(x) = f(x) + k

See also figure attached.

5 0
3 years ago
Please help asap, brainliest,thanks, and 50 points. Thank you soooo much! <3
Anuta_ua [19.1K]

Answers:

1) x^{8} y^{8}

2) y^{3} \sqrt{y}

3) 5x^{4} \sqrt{6}

4) \sqrt{7}

5) \frac{\sqrt{z}}{z}

Step-by-step explanation:

1) \sqrt{x^{16} y^{36}}

Rewriting the expression:

(x^{16} y^{36})^{\frac{1}{2}}

Multiplying the exponents:

x^{\frac{16}{2}} y^{\frac{36}{2}}

Simplifying:

x^{8} y^{8}

2) \sqrt{y^{7}}

Rewriting the expression:

\sqrt{y^{6} y}=(y^{6} y)^{\frac{1}{2}}

Multiplying the exponents:

y^{\frac{6}{2}} y^{\frac{1}{2}}

Simplifying:

y^{3} y^{\frac{1}{2}}=y^{3} \sqrt{y}

3) \sqrt{150 x^{8}}

Rewriting the expression:

\sqrt{(6)(25) x^{8}}

Since \sqrt{25}=5:

5x^{4}\sqrt{6}

4) \frac{7}{\sqrt{7}}

Multiplying numerator and denominator by \sqrt{7}:

\frac{7}{\sqrt{7}} (\frac{\sqrt{7}}{\sqrt{7}})=\frac{7}{7\sqrt{7}}

Simplifying:

\sqrt{7}

5) \frac{5z}{\sqrt{25 z^{3}}}

Rewriting the expression:

\frac{5z}{5z \sqrt{z}}

Simplifying:

\frac{1}{\sqrt{z}}

Since we do not want the square root in the denominator, we can multiply numerator and denominator by \sqrt{z}:

\frac{1}{\sqrt{z}}(\frac{\sqrt{z}}{\sqrt{z}})

Finally:

\frac{\sqrt{z}}{z}

3 0
4 years ago
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