All categories

2 years ago

I need help with the question !!

Mathematics

1 answer:

nikdorinn [45]2 years ago

8 0

Answer:

Step-by-step explanation:

x = 136/2 = 68°

You might be interested in

Use the x-intercept method to find all real solutions of the equation. x^3-10x^2+29x-20=0

stiks02 [169]

Answer:

X=1,5,4

Step-by-step explanation:

3 0

3 years ago

What is another way to write 54?

never [62]

Answer:

None of the above.

5 0

3 years ago

Read 2 more answers

What is the solution of the question 2(x+2)^2-4=28

Arisa [49]

2((x+2)(x+2)}-4=28
2{x^2 + 4x + 4}-4=28
2x^2 +4x=28
2(x^2+2x)=28
x^2+2x=28/2
x^2+2x=14

5 0

3 years ago

BRIANLIESTTT ASAP! PLEASE HELP ME :)

vagabundo [1.1K]

Answer:

A. $\displaystyle observational\:study$

Step-by-step explanation:

This takes alot of extended research before you even think about using the drug on patients.

I am joyous to assist you anytime.

7 0

3 years ago

Find gradient xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for dy/dx :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

4 0

3 years ago