2 years ago

How do you write 3.707 x 10-8^-8 in standard form? ASAP BRAINLIST

Mathematics

1 answer:

Paul [167]2 years ago

8 0

.00000003707 I believe

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MrRissso [65]

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Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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3 years ago

How do you write 3.707 x 10-8^-8 in standard form? ASAP BRAINLIST ​

How do you write 3.707 x 10-8^-8 in standard form? ASAP BRAINLIST