Answer:
if you convert the sugar in beverage A to the decimal .12 and compare it to beverage Bs .3 you'll find that B has 2.5 times more sugar than A.
Step-by-step explanation:
12 × 100= .12
.12 × 2.5= .30
Factors of 26 are 1, 2, 13, 26 all you have to do is figure out which numbers can go until a number and in this case the number is 26.
Answer:
8,100
Step-by-step explanation:
7,200 - 6,400 = 800 increased in 50. Years
What percentage is 800 of 6,400 (%/100 = is/of)
x/100 = 800/6400 (cross multiply)
(800*100)/6400 = 12.50%
(12.50 * 7200)/100 = 900 increased
7,200 + 900 = 8,100
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
Answer:
A= B= C= D= E= F=
Step-by-step explanation:
