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Ray Of Light [21]

3 years ago

13

On the last day of school the fifth grade class has a picnic at the city park. Exactly 182 students and 274 adults are signed up

for the picnic. Each picnic table seats 12 people. How many picnic tables will be needed for the picnic?
pls help!

1 answer:

mamaluj [8]3 years ago

5 0

Answer:

38 Tables

Step-by-step explanation:

First, we need to add the number of students with the number of adults to get the total number of people attending the picnic.

182 + 274 = 456

Next, we divide that number by how many people fit at each table to find how many tables we need.

456 people ÷ 12 people at each table = 38 tables.

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wariber [46]

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slega [8]

Answer: 31.43 cm

Step-by-step explanation:

The length of an arc is calculated using the formula:

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L = r∅

Since , the angle is given in degree , we will use the first formula.

L = $\frac{theta}{360}$ X 2 $\pi$ r

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3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

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where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
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We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
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$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
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So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
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where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

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Ne4ueva [31]

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3 years ago

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