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3 years ago

Calculate the number of Calories in a 5 fluid oz glass of red wine that contains 2.1 g carbohydrate and 13.8 g alcohol.

Chemistry

1 answer:

Tasya [4]3 years ago

6 0

Answer:

Explanation:

What are the 26 states of matter?

Bose–Einstein condensate.

Fermionic condensate.

Degenerate matter.

Quantum Hall.

Rydberg matter.

Rydberg polaron.

Strange matter.

Superfluid

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Describe an oxidation-reduction reaction.

DaniilM [7]

Answer: Oxidation reaction occurs when a reactant losses electrons in the reaction.

Reduction reaction occurs when a reactant gains electrons in the reaction.

Explanation: Reduction reaction : It is defined as the reaction in which a substance gains electrons. That means, the gain of electrons takes place.

Or we can say that, reduction reaction occurs when a reactant gains electrons in the reaction.

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

3 0

2 years ago

Consider the reaction to produce methanolCO(g) + 2H2 (g) <-----> CH3OHAn equilibrium mixture in a 2.00-L vessel is found t

MariettaO [177]

Answer : The value of $K_c$ of the reaction is 10.5 and the reaction is product favored.

Explanation : Given,

Moles of $CH_3OH$ at equilibrium = 0.0406 mole

Moles of $CO$ at equilibrium = 0.170 mole

Moles of $H_2$ at equilibrium = 0.302 mole

Volume of solution = 2.00 L

First we have to calculate the concentration of $CH_3OH,CO\text{ and }H_2$ at equilibrium.

$\text{Concentration of }CH_3OH=\frac{\text{Moles of }CH_3OH}{\text{Volume of solution}}=\frac{0.0406mole}{2.00L}=0.0203M$

$\text{Concentration of }CO=\frac{\text{Moles of }CO}{\text{Volume of solution}}=\frac{0.170mole}{2.00L}=0.085M$

$\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.302mole}{2.00L}=0.151M$

Now we have to calculate the value of equilibrium constant.

The balanced equilibrium reaction is,

$CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)$

The expression of equilibrium constant $K_c$ for the reaction will be:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.0203)}{(0.085)\times (0.151)^2}$

$K_c=10.5$

Therefore, the value of $K_c$ of the reaction is, 10.5

There are 3 conditions:

When $K_{c}>1$ ; the reaction is product favored.

When $K_{c}$ ; the reaction is reactant favored.

When $K_{c}=1$ ; the reaction is in equilibrium.

As the value of $K_{c}>1$ . So, the reaction is product favored.

7 0

3 years ago

A potassium atom can achieve a stable octet by

frez [133]

I think the answer is D, gaining one electron.

4 0

4 years ago

How do the isotopes of helium compare to one another?

Lesechka [4]

Hello! Charchar here!

Answer:

has an even shorter half-life. is around a hundred times higher. Rocks from the Earth's crust have isotope ratios varying by as much as a factor of ten; this is used in geology to investigate the origin of rocks and the composition of the Earth's mantle.

Explanation:

Google!

Hope this helped!

Have a nice day!

8 0

3 years ago

To find S, the number of shared

Anton [14]

Answer:

It’s 6 :)

Explanation:

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3 years ago