Answer: Several factors can influence the rate of a chemical reaction. In general, anything that increases the number of collisions between particles will increase the reaction rate, and anything that decreases the number of collisions between particles will decrease the chemical reaction rate.
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Explanation:
Answer:
First part: The new volume of the gas is 1786 Liters.
Second part: The temperature required to change the volume of the gas sample is 347 °C
Explanation:
We assume the Charles - Gay Lussac law where, in constant pressure, volume of a gas changes directly proportional to Temperature (in Kelvin)
V1 / T1 = V2/T2
37°C + 273 = 310 K
82°C + 273 = 355 K
1560L / 310°K = V2 / 355K
(1560 / 310) . 355 = V2
1786 L = V2
1560 L / 310 K = 3120 L / T2
T2 = 3120 L . (310 K / 1560 L)
T2 = 620 K
620K - 273 = 347°C
Answer:
1.2 M
Explanation:
If you use the dilution equation (M1V1=M2V2), you end up with (50)(12)=(500)(M2), and when you solve for M2 you get 1.2 M.
If 14 grams of hydrogen reacted with 24.7 grams of oxygen 27.7875 grams of water will be formed.
Explanation:
2H2+O2----------->2H2O.
- From the above equation, we can say that 4g of Hydrogen will react with 32 g of oxygen.
- In this question, Hydrogen is in excess amount.
- 32 g of Oxygen will react with = 4 g of H2.
- Therefore 24.7g of Oxygen will react with =24.7x4/32= 3.0875 g H2.
- The remaining 10.9125g of H2 will be left unreacted.
- Therefore the amount of water formed=(24.7+3.0875)=27.7875 g
