Answer:
The correct option of the first option
Explanation:
Dissolution of a solute in a solution is the process in which the solute interacts with the solvent leading to the disappearance of the solute to form a solution. Rate of dissolution is primarily affected by three factors namely
<u>Stirring of the solution</u>: Stirring the solution causes the solute to interact more with the solvent, <u>thus increasing the rate of dissolution</u>.
<u>Surface area of the solute</u>: The smaller the surface area of the solute, the more easier it is for it (the solute) to interact with the solvent. Hence, <u>the smaller the surface area, the faster the rate of dissolution</u>.
<u>Temperature of the solvent</u>: An increase in temperature of the solvent <u>causes the generally causes more things to dissolve in this solvent</u> due to increased energy of molecules in the solvent, which causes the molecules of the solute and solvent to interact more.
A decrease in the amount of solute<u> will reduce the amount of interaction the solute (since it is in lesser quantity) have with the solvent hence the rate of dissolution will also be low (even though a solution will still be formed)</u>.
Answer:
True
Explanation:
The amount of Hydrogen ion and hydroxide ion determines the acidity or alkalinity of an aqueous solution.
The higher the hydrogen ion content the higher the acidity of the solution. The increase in the amount of the hydrogen ion brings about decrease in the pH scale. The pH scale of about 0 - 2 has a very high hydrogen ion contents and as the Hydrogen ion decreases the pH value increases.
The higher the hydroxide ion contents the higher the alkalinity . The increase in the amount of hydroxide ion brings about increase in the pH value. The pH value of 12 - 14 depicts very strong alkalinity content. As the hydroxide ion increases the pH value increases.
If the hydroxide ion and hydrogen ions are of equal proportion the solution becomes neutral. The pH value for neutrality is 7.
Answer: I NEED POINTS!!!!
Explanation:
The molar mass of methanol is 12.01 + 4.04 + 16 = 32.05 g/mol
230.0 g of methanol / 32.05 g/mol = 7.176 mol methanol
The heat of combustion of methanol (CH3OH or CH4O) is -715.0 kJ/mol. (Negative sign means the energy is released)
Multiplying 7.176 mol by -715.0 kJ/mol gives -5,131 kJ.