Whats this i have been struggling for this . 5(3x−2)=−x−10

Mathematics

1 answer:

Inessa05 [86]2 years ago

6 0

Answer:

$x=0$

Step-by-step explanation:

$5(3x-2)=-x-10~(Given)\\\\15x-10=-x-10~(Distribute~5~to~3x-2)\\\\15x-10+x=-x-10+x~(Add~x~on~both~sides)\\\\16x-10=-10~(Simplify)\\\\16x-10+10=-10+10~(Add~10~on~both~sides)\\\\16x=0~(Simplify)\\\\\frac{16x}{16}=\frac{0}{16}~(Divide~16~on~both~sides)\\\\x=0~(Simplify)$

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What is the volume of a cylinder with base radius 4 and height 5?

Vsevolod [243]

Answer:

251.2 unit²

Step-by-step explanation:

Radius = 4 unit, height = 5 unit

Volume of cylinder = pi r² h

Where pi(#) = 3.14

Volume = # × 4² × 5

Volume = # × 16 × 5

Volume = 80# unit²

Volume = 80 × 3.14

Volume = 251.2 unit²

I hope this was helpful, please rate as brainliest

5 0

2 years ago

PLSS HELP ILL GIVE YOU BRAINLIEST!!

uysha [10]

Answer:

Step-by-step explanation:

Q1)

Use Phythogoras theorem:

$(AC)^2=(BC)^2+(AB)^2\\BC^2=AC^2-AB^2\\BC^2=6^2-4^2\\BC^2=36-16\\BC^2=20\\\\Apply\ square\ on\ both\ sides\\\\\sqrt{BC^2}=\sqrt{20} \\BC=\sqrt{20} \\BC=\sqrt{10(2)} \\BC=\sqrt{5(2)(2)} \\BC=2\sqrt{5}$

Q2)

Apply phythogoras theorem:

$CD^2=CE^2+DE^2\\CD^2=7^2+9^2\\CD^2=49+81\\CD^2=130\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{CD^2} = \sqrt{130} \\\\CD=\sqrt{130} \\\\CD=11.4$

Q3)

Apply phythogoras theorem again:

$BC^2=BD^2+CD^2\\BC^2=7^2+13^2\\BC^2=49+169\\BC^2=218\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{BC^2} =\sqrt{218} \\\\BC=\sqrt{218} \\\\BC=14.76$