Answer:
60 i think
Step-by-step explanation:
Hope this helped :)
<span>The charity needs at least 1001 entries to raise more than $25000.
Let n be the number of race entries, i be the income of the race, and c the cost of the race.
The money that the 5K brings in is given by
i = 25 * n + 5000
The cost is given by
c = n * 5
Now if the charity needs to raise more than 25000 then the income minus the cost must be greater than 25000.
25000 < i - c
subsituting for i and c
25000 < i - c = (25 * n + 5000 ) - (5 * n)
simplifying results in
25000 < 25*n - 5*n + 5000
25000 < 20*n + 5000
20000 < 20*n
1000 < n
The number of entries must be greater than 1000. Since entries must be an integer the charity needs at least 1001 entries.</span>
Answer:
A. Multiply the numerator and the denominator of each fraction by the denominator of the other fraction.
Answer:
(i) anti clockwise, at point (1，0)
(ii) (5,2)
Answer:
Step-by-step explanation:
