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3 years ago

Strat time 3:30 pm end time 7:00 pm what is the elapsed time.

Mathematics

2 answers:

Genrish500 [490]3 years ago

5 0

Answer :3 hrs
30minutes

Sergeeva-Olga [200]3 years ago

4 0

Answer:

3 hrs. 30 mins.

Step-by-step explanation:

7:00 - 3:30

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Each day her goal is to make 4 more baskets than she made thr day before. If she makes 10 baskets the first day and meets her go

irina [24]

Answer:

Janelle will make <u>62 baskets</u> on 14th day.

Step-by-step explanation:

Given,

Number of goals on 1st day = 10

We need to find the number of goals on 14th day.

Solution,

Since Janelle made 10 goals on 1st day and want to make 4 more basket from the day before.

So we can say that;

$a_1=10$ and $d=4$

And also $n=14$

here $a_1$ = first term

d = common difference

n = number of terms

Now we apply the formula of A.P.

$T_n=a_1+(n-1)d$

now substituting the given values, we get;

$T_{14}=10+(14-1)4\\\\T_{14}=10+13\times 4\\\\T_{14}=10+52 =62$

Hence Janelle will make <u>62 basket</u> on 14th day.

7 0

3 years ago

Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5

zaharov [31]

Answer:

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

$\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}$ or $\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}$

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

$\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}$

Therefore, the solution is 31.

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Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as $\displaystyle \large{a_{n-1} \cdot r = a_n}$ meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as: