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bazaltina [42]
2 years ago
6

The density of solid aluminum is 2. 70 g/cm3. If a 1g piece of aluminum is dropped in a cup of water, what will happen to the al

uminum? (the density of water is 1. 00 g/cm3. ) it will sink to the bottom. It will float to the top. It will hover in the middle. It will move up and down.
SAT
1 answer:
Vladimir79 [104]2 years ago
6 0
The answer you are looking for on this is ::
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What is the denominator of the simplified expression? 2 n
Shtirlitz [24]

The expression \frac{2n}{6n + 4} * \frac{3n + 2}{3n - 2} is a product expression

The denominator of the simplified fraction is 3n -2

<h3>How to determine the denominator?</h3>

The expression is given as;

\frac{2n}{6n + 4} * \frac{3n + 2}{3n - 2}

Divide the first fraction by 2/2

\frac{n}{3n + 2} * \frac{3n + 2}{3n - 2}\\

Evaluate the above product

\frac{n}{3n - 2}

The above fraction is a simplified fraction of \frac{2n}{6n + 4} * \frac{3n + 2}{3n - 2}, and the denominator is 3n - 2

Hence, the denominator of the simplified fraction is 3n -2

Read more about fractions at:

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What is the entropy change for the freezing process of 1 mole of liquid methanol at its freezing temperature (–97. 6˚c) and 1 at
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Answer:

the value of change in entropy for freezing process of 1 mole of liquid methanol is -18.07 J/mol.k

Explanation:

Entropy is defined as the measure of possible arrangement of the atoms or molecules. Entropy change for the the freezing process mole of 1 liquid methanol at -97.6 degree celcius and 1 atm will be -18.07 J/mol.

The entropy change can be calculated by the given formula:

 

Thus, the value of change in entropy for freezing process of 1 mole of liquid methanol is -18.07 J/mol.k

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What is x, the height of the cylinder? 21 units 24 units 25 units 28 units
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B 24 unitsAnswer:

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