Question

5-2(a+3b)/2 When a=4 and b=1.

Answer 1

Hello macelynn190!

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\huge \tt \frac{5 - 2(a + 3b)}{2}$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.

Given,

• a = 4
• b = 1

Now, substitute this in the place of 'a' & 'b'..

$\large \tt \frac{5 - 2(a + 3b)}{2} \\ = \large \underline{\underline{\tt \: \frac{5 - 2((4) + 3(1))}{2} }}$

Lastly, simplify it...

$\large \tt \: \frac{5 - 2((4) + 3(1))}{2} \\ = \large \tt\frac{5 - 2(4 + 3)}{2} \\ = \large \tt \: \frac{5 - 2(7)}{2} \\ = \large \tt \: \frac{5 - 14}{2} \\ = \large \tt\frac{-9}{2} \\ = \large \boxed{\boxed{ \bf \: -\frac{9}{2}=-4.5}}$

• The answer is -9/2 or -4.5

__________________

Hope it'll help you!

ℓu¢αzz ッ

Answer 2

Given info:-

Simplify: 5-2(a+3b)/2. When a=4 and b=1.

[5-2(a+3b)]/2

Now, put a=4 and b=1 (Because this is given in question only)

so,

⇛[5-2{4+3(1)}]/2

⇛[5-2{4+3}]/2

⇛[5-2{7}]/2

⇛[5-2×7]/2

⇛[5-14]/2

⇛-9/2 Ans.

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