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Firdavs [7]
2 years ago
10

Solve for H H=??????

Mathematics
1 answer:
Marrrta [24]2 years ago
6 0

Answer:

\frac{h-7}{10}=\frac{h+1}{2}

\frac{h-7}{10}\times \:10=\frac{h+1}{2}\times \:10

h-7=5\left(h+1\right)

h-7=5h+5

h-7+7=5h+5+7

h=5h+12

h-5h=5h+12-5h

-4h=12

\frac{-4h}{-4}=\frac{12}{-4}

h=-3

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Angle JKL is 54 degrees. What is the measure of angle MKL? *
hoa [83]

Answer:

MKL = 36°

Step-by-step explanation:

(3x + 6) + (6x + 12) = 54°

3x + 6x + 6 + 12 = 54

9x + 18 = 54

9x = 54 - 18

9x = 36

x = 36/9

x = 4

MKL = 6x + 12

MKL = 6(4) + 12

MKL = 24 + 12

MKL = 36°

6 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
I will give Brainliest on who answers this statement first.
ivanzaharov [21]

Answer:

hi

Step-by-step explanation:

8 0
3 years ago
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3 years ago
Find the volume of this sphere.<br> Use 3 for T.<br> V~ [?]in3<br> V = Tr3<br> r=4in
timofeeve [1]

Answer:

The answer is 256 in^{3}.

Step-by-step explanation:

To solve for the volume of the sphere, start by using the sphere volume formula, which is V = \frac{4}{3}  \pi  r^{3}. However, in this formula, 3 will be used instead of    (\pi).

Next, plug in the information given from the problem, and the formula will look like V = \frac{4}{3} (3) (4 in^{3}).    

Then, solve the equation, and the answer will be 256 in^{3}.

3 0
3 years ago
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